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3 years ago

If it passes through (6,-5) and m=2/3 solve for y , how would this be solved

Mathematics

2 answers:

Katen [24]3 years ago

6 0

(y-y1) = m( x-x1)

y+5=2/3(x-6)
y +5 = 2/3. x - 4
y = 2/3 x - 9

Sati [7]3 years ago

5 0

Set it up in slope-point intercept form.

y + 5 = 2/3(x - 6)

1. Distribute the 2/3.

y + 5 = 2/3x - 4

2. Subtract 5 from both sides.

y = 2/3x - 9

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At a canning company the daily production cost, y, is given by the quadratic equation y = 650 – 15x + 0.45x2, where x is the num

nevsk [136]

I think you plug in x= 150/9..?

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3 years ago

23.) Clarissa earns $300 per

Talja [164]

Answer:

e = 300 + .0275c

Step-by-step explanation:

So the earnings = e

Then she earns $300 and a bonus for cosmetics : 2.75%c which is equal to 0.0275 c or .0275c the c for cosmetics.

Thus the answer becomes :

e = $300 + .0275c

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3 0

3 years ago

What is the solution to 6x − 8 > 4x + 26

S_A_V [24]

Answer:

x > 17

Step-by-step explanation:

Combine like terms, We get:

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8 0

3 years ago

3. Create three quadratic equations that has one real solution.

Verizon [17]

Three quadratic equations that have one real solution are show below:

5x^2+3x^3+3^4 = 55

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7 0

3 years ago

An urn contains 13 red marbles and 11 blue marbles. 12 marbles are chosen at random. What is the probability that 7 red marbles

algol13

The probability of selecting or choosing seven marbles is 0.29.

Let E be the event of choosing seven red marbles.

According to the given.

Total number of balls in an urn = 13 + 11 = 24

Total number of red marbles = 13

Total number of blue marbles = 12

Now, the total number of ways of selecting 12 marbles from 24 = $^{24} C_{12}$

And the number of ways of selecting 7 red marbles = $^{13} C_{7} \times ^{11} C_{5}$

As, we know that, the probability of any event can be calculated as by taking the ratio of favroble outcomes to the total number of outcomes.

Therefore, the probability of selecting or choosing seven marbles is given by

$P(E) = \frac{^{13}C_{7}\times\ ^{11} C_{5} }{^{24} C_{12} }$

⇒ P(E) = $\frac{\frac{13!\times11!}{7!\times6!\times 5!\times6! } }{\frac{24!}{12!12!} }$

⇒ P(E) = 792792/2704156

⇒P(E) = 0.29

Hence, the probability of selecting or choosing seven marbles is 0.29.

Find out more information about probability here:

brainly.com/question/11234923

#SPJ4

3 0

2 years ago