Question

The system of equations can be solved using linear combination to eliminate one of the variables. 2x − y = −4→10x − 5y = −20 3x 5y = 59→3x 5y = 59 13x = 39 which equation can replace 3x 5y = 59 in the original system and still produce the same solution? 2x – y = –4 10x – 5y = –20 7x = 39 13x = 39

Answer 1

Answer:

Option D is correct.

13x = 39

Step-by-step explanation:

The system of equation is given:

$2x-y = -4$             ....[1]

$3x+5y = 59$         .....[2]

Multiply equation [1] by 5 to both sides we have;

$10x-5y = -20$              .....[3]

Using elimination method:

Add [2] and [3] equations to eliminate y and solve for x, we have;

$13x = 39$

Divide both sides by 13 we get;

x = 3

Substitute x in [1] we have;

2(3)-y = -4

6-y = -4

Subtract 6 from both sides we have;

-y = -10

Divide both sides by -1 we have;

y = 10

⇒Solution: (3, 10)

Therefore, an equation can replace 3x+5y = 59 in the original system and still produce the same solution is,

13x = 39

Answer 2

Answer:

13x=39

Step-by-step explanation: