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3 years ago

If the perimeter of a rectangle is 38 cm and the area is 78 square cm, then what are the dimensions of the rectangle?

1 answer:

8 0

The length is 13 and the width is 6. The way I figured it out is: find two factors of the area (that if multiplied with each other, they equal the area) and see which ones add up and then get multiplied by two to find the perimeter. I found 6 and 13 and then added them together to get 19. Then I multiplied 19 by two and got 38. This is how I have always done it idk.

Your answer is length = 13 and width = 6.
hope this helps :)

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Which equation represents a line that has a slope of 1/3 and passes through point -2, one

tensa zangetsu [6.8K]

Answer: y= 1/3 x + 5/3

Step-by-step explanation:

1= 1/3(-2) + b where b is the y intercept

1= -2/3 + B

+2/3 +2/3

B = 5/3

so we know the slope and the y- intercept

y= 1/3x + 5/3 check: 1=1/3(-2) +5/3

1 =1

8 0

3 years ago

Read 2 more answers

Determine the greatest common factor of 28xy^9z and 32x^2y^7z

RSB [31]

Answer:

GCF = 4xy⁷z

Step-by-step explanation:

Do Prime Factorizations for each term and select only those terms common to each:

28xy⁹z = 2·2·7·x·y·y·y·y·y·y·y·y·y·z

32x²y⁷z = 2·2·2·2·2·x·x·y·y·y·y·y·y·y·z

GCF = 2·2·x·y·y·y·y·y·y·y·z

GCF = 4xy⁷z

5 0

2 years ago

Place value of whole numbers 301,256,878

notka56 [123]

300 + 0+ 1, 200 + 50+ 6, 800 +70 + 8.

4 0

3 years ago

BD bisects m m Find m

amm1812

The text of the question is not visible in the answering window. I'll reproduce it here:

BD bisects <ABC.

m <ABD= 2.5x + 8.6

m<CBD = 3.5x - 3.4

Find m<ABC

Answer:

$m\angle ABC = 77.2^\circ$

Step-by-step explanation:

We have an angle ABC and a line BD bisecting it.

If an angle is bisected, then the two formed angles are congruent, that is

$m\angle ABD=m\angle CBD$

Substituting the algebraic expressions for both angles:

$2.5x + 8.6=3.5x - 3.4$

Subtracting 8.6 and 3.5x:

$2.5x - 3.5x = -8.6 - 3.4$

Operating:

$-x = -12$

$x = 12$

The two angles are:

$m\angle ABD=2.5x + 8.6=2.5(12) + 8.6=38.6^\circ$

$m\angle CBD=3.5x - 3.4 = 38.6^\circ$

As expected, both angles have the same measure.

The measure of the total angle ABC is twice any of those:

$m\angle ABC = 2*38.6^\circ=77.2^\circ$

$\mathbf{m\angle ABC = 77.2^\circ}$

6 0

3 years ago

Rewrite the expression 4+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B16-%284%29%285%29%7D" id="TexFormula1" title="\sqrt{16-(4)(

Inessa05 [86]

Answer:

$2+i$

Step-by-step explanation:

Given the expression:

$\dfrac{4+\sqrt{16-(4)(5)}}{2}$

To find:

The expression of above complex number in standard form $a+bi$ .

Solution:

First of all, learn the concept of $i$ (pronounced as <em>iota</em>) which is used to represent the complex numbers. Especially the imaginary part of the complex number is represented by $i$ .

Value of $i =\sqrt{-1}$ .

Now, let us consider the given expression:

$\dfrac{4+\sqrt{16-(4)(5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-(4\times 5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-20}}{2}\\\Rightarrow \dfrac{4+\sqrt{-4}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)(4)}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)}\sqrt4}{2}\\\Rightarrow \dfrac{4+\sqrt4i}{2} \ \ \ \ \ (\because \sqrt{-1} =i) \\\Rightarrow \dfrac{4+2i}{2}\\\Rightarrow 2+i$

So, the given expression in standard form is $2+i$ .

Let us compare with standard form $a+bi$ so we get $a =2, b =1$ .

$\therefore$ The standard form of

$\dfrac{4+\sqrt{16-(4)(5)}}{2}$

is: $\bold{2+i}$

8 0

2 years ago