Answer ASAP. Please give correct answer. (Involves a bunch of circles and trig identities)

Mathematics

1 answer:

iren [92.7K]2 years ago

7 0

Answer:

45.40

Step-by-step explanation:

First of all, the shape of rope is not a parabola but a catenary, and all catenaries are similar, defined by:

y=acoshxa

You just have to figure out where the origin is (see picture). The hight of the lowest point on the rope is 20 and the pole is 50 meters high. So the end point must be a+(50−20) above the x-axis. In other words (d/2,a+30) must be a point on the catenary:

a+30=acoshd2a(1)

The lenght of the catenary is given by the following formula (which can be proved easily):

s=asinhx2a−asinhx1a

where x1,x2 are x-cooridanates of ending points. In our case:

80=2asinhd2a

40=asinhd2a(2)

You have to solve the system of two equations, (1) and (2), with two unknowns (a,d). It's fairly straightforward.

Square (1) and (2) and subtract. You will get:

(a+30)2−402=a2

Calculate a from this equation, replace that value into (1) or (2) to evaluate d.

My calculation:

a=353≈11.67

d=703arccosh257≈45.40

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3 a western beach is reducing width by 10 feet every 5 years for the first 10 years the patter then became less constant dunes b

Anna71 [15]

A. Western Beach is reducing was width by 10 feet every 5 years for the first 10 years, then the pattern became less constant. Dunes Beach experienced a stable and fast increase in width, 25 feet every 5 years of 5 feet per year.

B. Somewhere between years 11 and 12 they had the same width.

C. You can place the values on a graph and connect the points, and look at the intersections to determine points in time where they were of the same width.

First, lets look at the data. Western Beach (or WB for short) decreases its width by 10 feet every 5 years from year 0 to year 10. Between year 11 and year 15 the pattern shifts and becomes less changing since there is barely any change between years 12 and 15. Dunes Beach (or DB) increases steadily by 25 feet every 5 years or 5 feet per year.

Assuming the changes in width happen over time and gradually, at some point between year 10 and 11, both beaches would have likely had the same width, somewhere between 70 and 75.

To determine the exact point in time where they meet we would need to draw a graph, with the width in feet on the X axis and the year on the Y axis. Then we place all the pairs in the graph by their coordinates, and connect the points that correspond to each beach. We then see where the lines intersect and use mathematics to determine the values of X and Y, giving us the time and width when the two beaches were equal.

please mark me brainliest it helps to become an genius

4 0

2 years ago

WILL MARK BRAINLIEST

mafiozo [28]

Answer:

0.21

Step-by-step explanation:

36%= .36

11/25= .44

4 0

2 years ago