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bonufazy [111]
4 years ago
15

Will mark you as brainliest. If your good with polynomials.

Mathematics
1 answer:
kobusy [5.1K]4 years ago
4 0
To solve/simplify this all you have to do is group like terms (the x^2's with each other, the x's with each other, and the normal numbers, -8)

14x^2-8+5x-6x^2+2x

group the x^2 (add 14x^2 to -6x^2)

8x^2-8+5x+2x

group the x's together (add 5x and 2x together)

8x^2+7x-8

Your answer will be d) 8x^2+7x-8



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inn [45]

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3 0
3 years ago
The dimensions of the base of Box 1 are x by 3x. The base area of Box 1 is: 3x 3x2 3x3 4x
Lunna [17]
<h3>The base area of box 1 is 3x^2\ square\ units</h3>

<em><u>Solution:</u></em>

Given that,

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To find: base area of box 1

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base\ area = length \times width\\\\base\ area = x \times 3x\\\\base\ area = 3x^2

Thus base area of box 1 is 3x^2\ square\ units

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