6x + 2y = 18
2y = -6x + 18
y = -3x + 9
The answer is 0.3413 because Explanation:
<span>z=<span><span>x−u</span>σ</span></span>, where <span>u=6 0andσ=10</span>.
Therefore the probability student finish the test between 50 to 60 minutes is,
<span>P<span>(50≤x≤60)</span>=P<span>(<span><span>50−60</span>10</span>≤z≤<span><span>60−60</span>10</span>)</span></span>
<span>P<span>(−1≤z≤0)</span>=P<span>(z≤0)</span>−P<span>(z≤−1)</span></span>
<span>=0.5000−0.1587=<span>0.3413</span></span>
Answer:
Step-by-step explanation:
We can use the Law of Sines to find segment AD, which happens to be a leg of 
and the hypotenuse of 
.
The Law of Sines states that the ratio of any angle of a triangle and its opposite side is maintained through the triangle:
Since we're given the length of CD, we want to find the measure of the angle opposite to CD, which is 
. The sum of the interior angles in a triangle is equal to 180 degrees. Thus, we have:
Now use this value in the Law of Sines to find AD:
Recall that 
and 
:
Now that we have the length of AD, we can find the length of AB. The right triangle is a 30-60-90 triangle. In all 30-60-90 triangles, the side lengths are in the ratio 
, where 
is the side opposite to the 30 degree angle and 
is the length of the hypotenuse.
Since AD is the hypotenuse, it must represent in this ratio and since AB is the side opposite to the 30 degree angle, it must represent in this ratio (Derive from basic trig for a right triangle and 
).
Therefore, AB must be exactly half of AD:
Answer:
Option 2: (1, 0) and (0, -5)
Step-by-step explanation:
Let's solve this system of equations using the elimination method.
Start by labelling the two equations.
5x -y= 5 -----(1)
5x² -y= 5 -----(2)
(2) -(1):
5x² -y -(5x -y)= 5 -5
Expand:
5x² -y -5x +y= 0
5x² -5x= 0
Factorise:
5x(x -1)= 0
5x= 0 or x -1= 0
x= 0 or x= 1
Now that we have found the x values, we can substitute them into either equations to solve for y.
Substitute into (1):
5(0) -y= 5 or 5(1) -y= 5
0 -y= 5 or -y= 5 -5
y= -5 or -y= 0
y= 0
Thus, the solutions are (0, -5) and (1, 0).
