Below are suppose the be the questions:
a. factor the equation
<span>b. graph the parabola </span>
<span>c. identify the vertex minimum or maximum of the parabola </span>
<span>d. solve the equation using the quadratic formula
</span>
below are the answers:
Vertex form is most helpful for all of these tasks.
<span>Let </span>
<span>.. f(x) = a(x -h) +k ... the function written in vertex form. </span>
<span>a) Factor: </span>
<span>.. (x -h +√(-k/a)) * (x -h -√(-k/a)) </span>
<span>b) Graph: </span>
<span>.. It is a graph of y=x^2 with the vertex translated to (h, k) and vertically stretched by a factor of "a". </span>
<span>c) Vertex and Extreme: </span>
<span>.. The vertex is (h, k). It is a maximum if "a" is negative; a minimum otherwise. </span>
<span>d) Solutions: </span>
<span>.. The quadratic formula is based on the notion of completing the square. In vertex form, the square is already completed, so the roots are </span>
<span>.. x = h ± √(-k/a)</span>
Answer:
Step-by-step explanation:
Remark
You better be issuing a very small number of tickets.
Tickets vowels: a e i o u
Primes < 10: 2 3 5 7
Probability(e and 5) = 1/5 * 1/4 = 1/20
Answer: 1/20
Answer:0.05
You should probabily give 0.05 as your answer.
Answer:
40π in^2
Step-by-step explanation:
360°/72°=5
so, each of the two shaded regions are 1/5 of the circle.
the formula for finding the area of a circle is πr^2, so:
area for one of the shaded regions:
1/5πr^2
1/5π(10)^2
1/5π100
20π in^2
this means that the area for one of the shaded regions is 20π. however, since there are two of them:
2(20π)=40π
so, the area of the shaded regions is 40πin^2
We are trying to find the average speed of the plane, which is mph, or
. Using proportions, we can find the average speed of the plane in mph:

- Use the information from the problem to create a proportion. Remember that we are looking for mph, so we will call that
.

- Multiply the entire equation by


- Divide both sides of the equation by
to clear both sides of the mile unit
The average speed of the plane is 300 mph.