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3 years ago

4.

Mathematics

1 answer:

antiseptic1488 [7]3 years ago

7 0

Step-by-step explanation:

the above pic is the ans of this question

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What is 9 devided by 7192

iris [78.8K]

The answer is 0.00125139043

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3 years ago

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Henrietta is mixing paint for an art project. She uses 2 cups of red paint for every 3 cups of yellow paint for each batch. If s

bezimeni [28]

2/3=6/x
2x=6*3
2x=18
x=18/2
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2 years ago

Directions: Find the complemen

andre [41]

Given:

The angles are:

Example $54^\circ$

1. $63^\circ$

2. $87^\circ$

3. $45^\circ$

4. $72^\circ$

5. $5^\circ$

To find:

The complimentary angle of the given angles.

Solution:

If two angles are complimentary, then their sum is 90 degrees.

Example: Let x be the complimentary angle of $54^\circ$ , then

$x+54^\circ=90^\circ$

$x=90^\circ -54^\circ$

$x=36^\circ$

Similarly,

1. The complimentary angle of $63^\circ$ is:

$90^\circ -63^\circ=27^\circ$

2. The complimentary angle of $87^\circ$ is:

$90^\circ -87^\circ=3^\circ$

3. The complimentary angle of $45^\circ$ is:

$90^\circ -45^\circ=45^\circ$

4. The complimentary angle of $72^\circ$ is:

$90^\circ -72^\circ=18^\circ$

5. The complimentary angle of $5^\circ$ is:

$90^\circ -5^\circ=85^\circ$

Therefore, the complimentary angles of $54^\circ, 63^\circ, 87^\circ, 45^\circ, 72^\circ, 5^\circ$ are $36^\circ, 27^\circ, 3^\circ, 45^\circ, 18^\circ, 85^\circ$ respectively.

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3 years ago

Please help ASAP the answer are within the pic

DerKrebs [107]

Hey Ive taken this assesment. The answer is 55

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3 years ago

What are the endpoint coordinates for the midsegment of △BCD that is parallel to BC?

natulia [17]

Answer:

The endpoint coordinates for the mid-segment are: $(-2,-1)$ and $(1,0)$

Step-by-step explanation:

According to the given diagram, the coordinates of the vertices of $\triangle BCD$ are: $B(-3,1), C(3,3)$ and $D(-1,-3)$

Now, the endpoints of the mid-segment of $\triangle BCD$ which is parallel to $BC$ will be the mid-points of sides $BD$ and $CD$ .

Formula for the coordinate of mid-point : $(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})$ , where $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ are two endpoints.

So, the mid-point of $BD$ will be: $(\frac{-3-1}{2},\frac{1-3}{2})=(\frac{-4}{2},\frac{-2}{2})=(-2,-1)$

and the mid-point of $CD$ will be: $(\frac{3-1}{2},\frac{3-3}{2})=(\frac{2}{2},\frac{0}{2})=(1,0)$

Thus, the endpoint coordinates for the mid-segment of $\triangle BCD$ that is parallel to $BC$ are $(-2,-1)$ and $(1,0)$

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2 years ago

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