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NikAS [45]
3 years ago
14

4.

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
7 0

Step-by-step explanation:

the above pic is the ans of this question

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What is 9 devided by 7192
iris [78.8K]
The answer is 0.00125139043
8 0
3 years ago
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Henrietta is mixing paint for an art project. She uses 2 cups of red paint for every 3 cups of yellow paint for each batch. If s
bezimeni [28]
2/3=6/x
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5 0
2 years ago
Directions: Find the complemen
andre [41]

Given:

The angles are:

Example 54^\circ

1. 63^\circ

2. 87^\circ

3. 45^\circ

4. 72^\circ

5. 5^\circ

To find:

The complimentary angle of the given angles.

Solution:

If two angles are complimentary, then their sum is 90 degrees.

Example: Let x be the complimentary angle of 54^\circ, then

x+54^\circ=90^\circ

x=90^\circ -54^\circ

x=36^\circ

Similarly,

1. The complimentary angle of 63^\circ is:

90^\circ -63^\circ=27^\circ

2. The complimentary angle of 87^\circ is:

90^\circ -87^\circ=3^\circ

3. The complimentary angle of 45^\circ is:

90^\circ -45^\circ=45^\circ

4. The complimentary angle of 72^\circ is:

90^\circ -72^\circ=18^\circ

5. The complimentary angle of 5^\circ is:

90^\circ -5^\circ=85^\circ

Therefore, the complimentary angles of 54^\circ, 63^\circ, 87^\circ, 45^\circ, 72^\circ, 5^\circ are 36^\circ, 27^\circ, 3^\circ, 45^\circ, 18^\circ, 85^\circ respectively.

6 0
3 years ago
Please help ASAP<br>the answer are within the pic
DerKrebs [107]

Hey Ive taken this assesment. The answer is 55


6 0
3 years ago
What are the endpoint coordinates for the midsegment of △BCD that is parallel to BC?
natulia [17]

Answer:

<em>The endpoint coordinates for the mid-segment are:  (-2,-1) and (1,0)</em>

Step-by-step explanation:

According to the given diagram, the coordinates of the vertices of \triangle BCD are:   B(-3,1), C(3,3) and D(-1,-3)

Now, the endpoints of the mid-segment of \triangle BCD which is parallel to BC will be the mid-points of sides BD and CD.

<u>Formula for the coordinate of mid-point</u> :   (\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}), where (x_{1}, y_{1}) and (x_{2}, y_{2}) are two endpoints.

So, the mid-point of BD will be:  (\frac{-3-1}{2},\frac{1-3}{2})=(\frac{-4}{2},\frac{-2}{2})=(-2,-1)

and the mid-point of CD will be:  (\frac{3-1}{2},\frac{3-3}{2})=(\frac{2}{2},\frac{0}{2})=(1,0)

Thus, the endpoint coordinates for the mid-segment of \triangle BCD that is parallel to BC are  (-2,-1) and (1,0)

4 0
2 years ago
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