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Tomtit [17]
3 years ago
10

Fraction that is equivalent to but different from 4/13​

Mathematics
1 answer:
dem82 [27]3 years ago
4 0

Answer:

8/26

Step-by-step explanation:

All you have to do is multiply the numerator and denominator with the same number. For example, I did 2. 4x2=8, and 2x13=26.

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In Illinois, 9% of all drivers arrested for DUI (Driving Under the Influence) are repeat offenders; that is, they have been arre
Veseljchak [2.6K]

Answer:

a) 21.58% probability that exactly 3 people are repeat offenders

b) 97.91% probability that at least one person is a repeat offender

c) 3.69

d) 1.83

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

9% of all drivers arrested for DUI (Driving Under the Influence) are repeat offenders

This means that p = 0.09

41 people arrested for DUI in Illinois are selected at random.

This means that n = 41

a. What is the probability that exactly 3 people are repeat offenders?

This is P(X = 3).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{41,3}.(0.09)^{3}.(0.91)^{38} = 0.2158

21.58% probability that exactly 3 people are repeat offenders

b. What is the probability that at least one person is a repeat offender?

Either none are repeat offenders, or at least one is. The sum of the probabilities of these outcomes is 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1).

Then

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = 0) = C_{41,0}.(0.09)^{0}.(0.91)^{41} = 0.0209

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0209 = 0.9791

97.91% probability that at least one person is a repeat offender

c. What is the mean number of repeat offenders?

E(X) = np = 41*0.09 = 3.69

d. What is the standard deviation of the number of repeat offenders?

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{41*0.09*0.91} = 1.83

4 0
3 years ago
Sharon has collected donations of $4.40, $3.12, $8.00, and $6.22 to help buy books for the new library. What is the mean (averag
jekas [21]

Answer:5.435

Step-by-step explanation: In math, the average value in a set of numbers is the middle value, calculated by dividing the total of all the values by the number of values. To find this answer, we need to find the average of a set of data, we add up all the values and divide this total by the numbers of values. So if you add 4.40, 3.12, 8.00 and 6.22 together, we get 21.74. There are four values (4.40, 3.12, 8.00 and 6.22) so we divide the amount of values there are, which would be four. 21.47/4 would then get you 5.435

3 0
3 years ago
A circle with center at (12,−1) passes through (0,−1). Find the circumference and area of the circle in terms of p.
madreJ [45]

Answer:

C = 75.36

A = 452.16

Step-by-step explanation:

Find the radius r by finding the distance between (12,-1) and (0,-1) using the distance formula.

d = \sqrt{(12-0)^2 + (-1--1)^2} =\sqrt{(12)^2 + (0^2} =\sqrt{144+0} =\sqrt{144}=12

The radius is 12.

So the circumference of the circle is C = 2\pi r = 2\pi 12 = 24\pi = 75.36

So the area of the circle is A = \pi r^2\\A = \pi 12^2\\A = 144\pi\\A = 452.16

6 0
3 years ago
What is the total depreciation (at 10% rate) on a blower purchased 3 years ago for $499?
GrogVix [38]

\bf \qquad \textit{Amount for Exponential Decay} \\\\ A=P(1 - r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &499\\ r=rate\to 10\%\to \frac{10}{100}\dotfill &0.10\\ t=\textit{elapsed time}\dotfill &3\\ \end{cases} \\\\\\ A=499(1-0.10)^3\implies A=499(0.9)^3\implies A=363.771 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{\textit{total depreciation 499 - 363.771}}{135.229}~\hfill

6 0
3 years ago
8.
andrey2020 [161]

Answer:

Do you want the perimeter of this shape?

5 0
3 years ago
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