Question

Select the correct answer.

Answer 1

Answer:

See explanation

Step-by-step explanation:

The question is incomplete, as the function is not given. So, I will make an assumption.

A quadratic function is represented as:

$f(x) = ax^2 + bx + c$

If $a > 0$, then the function has a minimum x value

E.g. $f(x) = 4x^2 - 5x + 8$ ------ $4 > 0$

Else, then the function has a maximum x value

E.g. $f(x)= -4x^2 -5x + 8$ ---- $-4 < 0$

The maximum or minimum x value is calculated using:

$x = -\frac{b}{2a}$

For instance, the maximum of $f(x)= -4x^2 -5x + 8$ is:

$x = -\frac{-5}{2*-4}$

$x = -\frac{5}{8}$

So, the maximum of the function is:

$f(x)= -4x^2 -5x + 8$

$f(-\frac{5}{8}) = -4 * (-\frac{5}{8})^2 - 5 *(-\frac{5}{8}) +8$

$f(-\frac{5}{8}) = 9.5625$