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nikdorinn [45]
3 years ago
15

Please help me!!! show work

Mathematics
1 answer:
WINSTONCH [101]3 years ago
3 0

Answer:x=8 or x=-2

Step-by-step explanation:

log4(x-6) + log4(x)=2

log4(x(x-6))=2

4^2=x(x-6)

4x4=x(x-6)

16=x^2-6x

Arrange the quadratic equation

x^2-6x-16=0

x^2+2x-8x-16=0

x(x+2)-8(x+2)=0

(x-8)(x+2)=0

x-8=0. x+2=0

x=8. x=-2

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Shkiper50 [21]

The correct option is C no, both 3.61^2 and 3,62^2 are greater than 13.

<h3>Is he correct? If not, what was his mistake?</h3>

To check this, we can just square both of the bounds that he found, and see if it makes sense.

Walter says hat:

3.61 < √13 < 3.62

Then we must have:

(3.61)^2 < 13 < (3.62)^2

The lower bound is 3.61, if we square it we get:

3.61*3.61 = (3 + 0.61)*(3 + 0.61) = 9 + 6*0.61 + 0.61*0.61 = 13.0321

Now, this is larger than 13, so the above inequality is false, which means that Walter is incorrect, because both 3.61 and 3.62 are larger than √13 , then the correct option is C.

If you want to learn more about square roots:

brainly.com/question/98314

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8 0
2 years ago
What is 7/8 + 1/4 * 5/6 evaluated and simplified into a fraction?
kramer
7/8 + 1/4 * 5/6....no parenthesis means we do the multiplication first

7/8 + 5/24 =
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4 years ago
What is the inverse of the function f(x) = one-quarterx – 12?
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Answer:

f^(-1)(x) = 4x + 48.

Step-by-step explanation:

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This is equivalent to the line y = 1/4 x - 12.

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Now solve for y:

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y = 4x + 48

So the inverse f^(-1)(x) = 4x + 48.

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