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3 years ago

How to work the problems out and the answers to 3 of my homework questions?

Mathematics

2 answers:

SashulF [63]3 years ago

7 0

I think 1/4 might be your answer

Kay [80]3 years ago

7 0

1/4 is your answer i know because i learned that before

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HELP!! ILL GIVE BRAINLIEST!!!! PLS SPSPLSPSLSPSLS

MAVERICK [17]

B.......................

7 0

3 years ago

In an attempt to escape a desert island, a castaway builds a raft and sets out to sea. The wind shifts a great deal during the d

nikdorinn [45]

Answer:

R = 7,34 km

Ф = 63,43° north of east

Step-by-step explanation:

Let´s analyze each movement and find its perpendicular components. Then, we are going to add the components along the x and y axes to get the resultant and finally to calculate its magnitude and direction.

To determine the perpendicular components, we will use right triangles trigonometrics ratios.

Please see images for each displacement in attached file.

Displacement A: 2.50 km and 45° north of west

Ax= AcosФ = 2.50cos45° = 1.77 km (neg. direction)

Ay= AsenФ = 2.50sen45° = 1.77 km (pos. direction)

Displacement B: 4.70 km and 60° south of east

Bx= BcosФ = 4.70cos60° = 2,35 km (pos. direction)

By= BsenФ = 4.70sen60° = 4,07 km (neg. direction)

Displacement C: 1.30 km and 25° south of west

Cx= CcosФ = 1.30cos25° = 1,18 km (neg. direction)

Cy= CsenФ = 1.30sen25° = 0.55 km (neg. direction)

Displacement D: 5.10 km due east (0°)

Dx= DcosФ = 5.10 km (pos. direction)

Dy= DsenФ = 0 km

Displacement E: 1.70 km and 5° east of north

Ex= EsenФ = 1.70sen5° = 0,15 km (pos. direction)

Ey= EcosФ = 1.70cos5° = 1.69 km (pos. direction)

Displacement F: 7.20 km and 55° south of west

Fx= FcosФ = 7.20cos55° = 4.13 km (neg. direction)

Fy= FsenФ = 7.20sen55° = 5.90 km (neg. direction)

Displacement G: 2.80 km and 10° north of east

Gx= GcosФ = 2.80cos10° = 2.76 km (pos. direction)

Gy= GsenФ = 2.80sen10° = 0.49 km (pos. direction)

Now, we add the components along the x- and y- axis to find the components of the resultant (R):

Rx = Ax + Bx + Cx + Dx + Ex + Fx + Gx

Ry = Ay + By + Cy + Dy + Ey + Fy + Gy

Therefore,

Rx= (-1.77)+(2.35)+(-1.18)+(5.10)+(0.15)+(-4.13)+(2.76)

Ry= (1.77)+(-4.07)+(-0.55)+(0)+(1.69)+(-5.90)+(0.49)

Note: minus (-) symbol to negative directions

Rx = 3.28 km

Ry = - 6.57 km

Let´s use the Theorem of Pythagoras to find the magnitud ot the resultant:

$R = \sqrt{Rx^{2} +Ry^{2} }$

$R =\sqrt{(3.28)^{2}+(-6.57)^{2} }$

R = 7,34 km

To find the direction of the resultant:

tanФ = $\frac{Ry}{Rx}$

tanФ = $\frac{6.57}{3.28}$

tanФ = 2.00

Ф = tan-1 (2.00)

Ф = 63,43° north of east

Download pdf

3 0

4 years ago

2 intersecting lines are shown. A line with point T, R, W intersects a line with points S, R, V at point R. Clockwise, from the

kolezko [41]

Answer:

Step-by-step explanation:

a) sum of angle on the straight line TRW is 180.

Given <TRS = 2x+10

<SRW = x-10

<TRS+<SRW = 180

2x+10+x-10 = 180

3x = 180

x = 180/3

x = 60°

<TRV = 180°-(2x+10)

Substitute x = 60° into the expression

<TRV = 180-(2(60)+10)

<TRV = 180-(120+10)

<TRV = 180-130

<TRV = 50°

2) From the diagram attached <MHJ= <LHK (oppositely directed angle)

Given

<MHJ= x+15

<LHK = 2x-20

Substitute the given data into the formula to get x

x+15= 2x-20

x-2x = -15-20

-x = -35

x = 35°

Next is to get the measure of <MHJ

<MHJ = x+15

<MHJ = 35+15

<MHJ = 50°

8 0

3 years ago

URGENT! When we solve (cos²x - 1 = 0) by adding and taking the square root, how come we get the same answer when we factor (cos²

boyakko [2]

Answer:

Step-by-step explanation:

4 0

3 years ago

If b=a-c are supplementary angle find the value of a

leonid [27]

Answer:

a=b+c

Step-by-step explanation:

Dunno if that's what you're looking for, but that's what I got from what you gave

3 0

3 years ago