The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
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LETS prove the 2nd part of the Question
Here concept of right angles is used
We can see BA is perp to BD
and BC is perp to BE
We have to prove angle 1 = angle 3
i will denote angle by a
therefore we need to prove a1 = a3
as BA is perp to BD hence angle between them will be 90 degree
a1 + a2 = 90 degree
Similarly BC is perp to BE
a2 + a3 = 90 degree
as both equations add up gives 90 degree so will equate them
a1 + a2 = a2 + a3
which means a1 = a3
Hence Proved
To learn more about Right Angles:
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Answer:
74
Step-by-step explanation:
The possiblities that exist:
H, H, H
H, H, T
H, T, H <----
H, T, T
T, H, H
T, H, T
T, T, H
T, T, T
The answer is 1/8. Now the problem that you gave us isn't dependent upon anything, so more specifically the answer is 1/8 independent.
Nothing has actually happened therefore no odds have been decreased or increased.
C. they are worth the same amount of money, 1/2 and 2/4 are both 50% or 50 cents
