10. A(2, 3), B(2,9), C(6, 6), D(8,5), E(8, 11), F(12, 8)
olga nikolaevna [1]
I can’t see the picture so can you put it up
Answer:
146.3m²
Step-by-step explanation:
area of quarter circle=1/4π×8²
=50.3m²
area of the square=s²
8×8=64m²
area of the triangle=1/2bh
1/2×8×8=32m²
total area=50.3+64+32=146.3m²
Answer:
8
Step-by-step explanation:
The diagram shows 8 different endpoints, so there are 8 different possible outcomes.
You can list all outcomes:
HHH
HHT
HTH
HTT
THH
THT
TTH
TTT
where H - head, T - tail
In any equation with variables, you want to end with a variable isolated on one side with no coefficients(like x=4, for instance).
So, with that in mind, let's solve number 2.
5(x-3) - 2(2x+4) = -2(x-2)
Let's distribute the coefficients.
(5x-15)-(4x+8) = (-2x+4)
Simplify the left side first (by subtracting the two)
5x-4x = x
-15 - (+)8 = -23
So, left side is
x-23 = -2x+4
We're close now, just bring the x to the left side and the other values to the right
x-23 = -2x+4
+23 +23
x=-2x+27
+2x +2x
3x=27
divide by 3
x=9
3.
3(4x-5)-2(2x-2)=4(3x-2)+5
Same idea here; distribute the coefficients, and simplify.
(12x-15)-(4x-4)=(12x-8)+5
12x-4x=8x
-15-(-)4=-11
-8+5=-3
8x-11=12x-3
bring x to left, other numbers to right
-12x -12x
+11 +11
-4x = 8
divide by -4
x=-2
Use u subsitution the solve by grouping
u=x^2
u^3-16u=4u^2-64
u^3-4u^2-16u+64=0
(u^3-4u^2)+(-16u+64)=0
u^2(u-4)+(-16)(u-4)=0
(u^2-16)(u-4)=0
(u-4)(u+4)(u-4)=0
(u+4)(u-4)^2=0
u=x^2
(x^2+4)(x^2-4)^2=0
(x^2+4)((x-2)(x+2))^2=0
(x^2+4)(x-2)²(x+2)²=0
set to zero
x^2+4=0
x^2=-4
x=+/-2i
x-2=0
x=2
x+2=0
x=-2
the other roots are -2 and 2
for graphinc calculator, graph and find x intercepts
