2(3t - 1) - 5(t - 1)
2(3t) - 2(1) - 5(t) + 5(1)
6t - 2 - 5t + 5
6t - 5t - 2 + 5
t + 3
Answer: A) 20.9 ; B) 34years
Step-by-step explanation:
Given the following :
AGE (X) - - - - - - - 19 - -20 - - - 21 - - - 22 - - - 23
FREQUENCY (F) - 2 - - 3 - - - - 1 - - - - 4 - - - - 1
A)
MEAN(X) = [AGE(X) × FREQUENCY (F)] ÷ SUM OF FREQUENCY
F*X = [(19 * 2) + (20 * 3) + ( 21 * 1)+(22 * 4)+(23 * 1)]
= 38 + 60 +21 + 88 + 23 = 230
SUM OF FREQUENCY = 2 + 3 + 1 + 4 + 1= 11
MEAN(X) = 230 / 11
X = 20.9
B)
WHEN A NEW PLAYER WAS ADDED :
MEAN (X) = 22
Let age of new player = y
Sum of Ages = 19 + 19 +20 + 20 + 20 + 21 + 22 + 22 + 22 + 22 + 23 + y
Number of players = 11 + 1 = 12
Mean(x) = sum of ages / number of players
New mean (x) = 22
x = (230 + y) / 12
22 = (230 + y) / 12
Cross multiply
264 = 230 + y
y = 264 - 230
y = 34 years
Answer:
0.4437
Step-by-step explanation:
First we will define independent events.
Two events are said to be independent when the occurrence of one event doesn't affect the probability of occurrence of second event.
Given
P(Q)=0.87
and
P(R)=0.51
The probability of independent events is given as:
P(Q∩R)=P(Q)*P(R)
=0.87*0.51
=0.4437
So the probability of Q and R is 0.4437 ..
First we look at the equation an determine our common denominator.
(X²-X-6) / X² = (X-6) / 2X + (2X+12) / X (let's use 2X² as the comm denom)
multiply the first fraction by 2, the second by X, and the third by 2x
(2x²-2x-12) / 2x² = (x²-6x) / 2x² + (4x²+24x) / 2x² (dropping the denominator)
2x² - 2x - 12 = x² - 6x + 4x² + 24x (simplify)
-3x² - 20x - 12 (multiply by -1)
3x² + 20x + 12
(x + 6) (3x + 2) (factored version)
Note that your function can be written as
So, if x is negative, your function is identically equal to 1. In particular, the limit as x approaches -2 will be 1 as well.
