Given - Taisha has a general goal is to burn the 280 calories.
she is varies by the 25 calories.
Find out the maximum and minimum of calories burn by the taisha.
To proof -
let us assume that the calories burn by the taisha be x.
as given the calories are varies by the 25 calories.
then the maximum calories equation becomes
x-25 = 280
x = 280 + 25
x = 305
the maximum calories burn by the taisha is 305 calories.
minimum calories equationbecomes
x + 25 = 280
x = 255
The minmum calories burn by the taisha is 255 calories.
Hence proved
<span>Slope-intercept form is Y = MX + B. This is in standard form, AX + BY = C. You have to move the X to the other side of the equation and simplify it. </span>
<span>10x - 2y = 10 </span>
<span>- 10x - 10x Subtract 10x from both sides </span>
<span>- 2y = - 10x + 10 Now everything is in the right place, but it still needs to be simplified. </span>
<span>Divide each term by -2, in order to isolate the variable Y. </span>
<span>- 2y/ - 2 = - 10x/ - 2 + 10/ - 2 </span>
<span>The answer is: y = 5x - 5</span>
Answer:4 In 2+4 In x
Step-by-step explanation:
Got it right on edge
Positive 3. Absolute values are never negative, they are either 0 or a positive. so -3 would be +3
