Answer:
y = -2x+5
Step-by-step explanation:
y = -2x+1 is in the form y= mx+b where m is the slope and b is the y intercept
-2 is the slope
Parallel lines have the same slope so our new line will have the same slope
y = -2x+b
The point given is the y intercept (value when x is zero)
b = 5
y = -2x+5
Answer:
7.) 18.86m
8.) 15 inches
9.) 32 and 34
10.) 21 and 29
11.) change all the decimals in the equation into fractions.
Step-by-step explanation:
Option C
For each value of y, -2 is a solution of -21 = 6y - 9
<u>Solution:</u>
Given, equation is – 21 = 6y – 9
We have to find that whether given set of options can satisfy the above equation or not
Now, let us check one by one option
<em><u>Option A) </u></em>
Given option is -5
Let us substitute -5 in given equation
- 21 = 6(-5) – 9
- 21 = -30 – 9
- 21 = - 39
L.H.S ≠ R.H.S ⇒ not a solution
<em><u>Option B)</u></em>
Given option is 3
- 21 = 6(3) – 9
- 21 = 18 – 9
- 21 = 9
L.H.S ≠ R.H.S ⇒ not a solution
<em><u>Option C)</u></em>
Given option is -2
- 21 = 6(-2) – 9
- 21 = - 12 – 9
- 21 = - 21
L.H.S = R.H.S ⇒ yes a solution
<em><u>Option D)</u></em>
- 21 = 6(9) – 9
- 21 = 54 – 9
- 21 = 45
L.H.S ≠ R.H.S ⇒ not a solution
Hence, the solution for the given equation is – 2, so option c is correct
Step-by-step explanation:
15) 50 ÷ 2 = 25
17) Mean = 301, Mode = 40-50
(10+20) ÷ 2 = 15, (20+30) ÷ 2 = 25, (30+40) ÷ 2 = 35
(40+50) ÷ 2 = 45, (50+60) ÷ 2 = 55, (60+70) ÷ 2 = 65
(70+80) ÷ 2 = 75
• 15×4 = 60, 25×8 = 200, 35×10 = 350, 45×12 = 540
55×10 = 550, 65×4 = 260, 75×2 = 150
Mean = (60+200+350+540+550+260+150) ÷ 7
= 2110 ÷ 7
= 301.4285....
= 301
Mode : the highest frequency
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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