The force being exerted by the cord is m(a+g) if the bucket is being accelerated upward.
If T = 70 N, then <span>a=70N/5.2kg−9.8m/<span>s2</span>=3.66m/<span>s2</span></span>is the maximum acceleration that it could have.
Starting from rest, <span>Δy = 1/2a<span>t2</span>→ t = </span>√2Δy/a = <span>√</span>2∗12.5/3.66 = 2.61s
Option C is your answer.
9x² + 6x + 1
9x² + 3x + 3x + 1
3x(3x + 1) + 1(3x + 1)
(3x + 1)(3x + 1)
5 x 5 / 2 This problem is super easy because i am in Kamehameha Schools and the answer to this problem is 12.5