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olchik [2.2K]
4 years ago
13

Solve the equation.

Mathematics
1 answer:
luda_lava [24]4 years ago
5 0

Hope you liked that.

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Choose the odd one out. Give a reason for your answer. 75%. 3/4. 0.75. 7.5
kumpel [21]

Answer:

7.5

Step-by-step explanation:

when implementing the joe mama constant into our quadratic formula, we can solve to find that 7.5 does not uphold when subjected to the same peen coefficient checks that all other values held true for.

6 0
3 years ago
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I need help with this hw please
Tcecarenko [31]

Answer:

a. 6  b. |-23|  c. |-72|  d. 29  g. <  h. >  q. -1, 0, |-2|, |-3|

r. -2, -1, |1|, |-2|  s. -26, -24, |-20|, 21  t. -201, 120, |-121|, 210

Step-by-step explanation:

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4 0
4 years ago
Which two values of x are roots
FrozenT [24]
The answer is C. 

To solve these types of equations you first need to make sure that you equation is equal to 0. In this case all of the numbers are already on the same side so no work needs to be done there. Then we can get a, b and c values for the quadratic equation by looking at the coefficients. 

a = 4 (number attached to x^2)
b = -6 (number attached to x)
c = 1 (number with no variable attached)

Now we can put this into the quadratic equation. 

\frac{-b +/-  \sqrt{ b^{2} -4ac} }{2a}

\frac{6 +/- \sqrt{ -6^{2} -4(4)(1)} }{2(4)}

\frac{6 +/- \sqrt{20} }{8}
6 0
4 years ago
Find all solutions to the equation cos x cox(3x)+sin x sin(3x)=0 on the interval [0,2pi]
lyudmila [28]

Answer:

Step-by-step explanation:

cos x cos (3x)+sinx sin (3x)=0

cos (x-3x)=0

cos(-2x)=0

cos 2x=0=cos (2n+1)π/2

where n=0,1,2,3∞∞∞∞

2x=(2n+1)π/2

x=(2n+1)π/4

put n=0,1,2,3

x=π/4,3π/4,5π/4,7π/4

6 0
3 years ago
Please helpppppp i will mark you braliest
notsponge [240]

Answer:

0.3

Explanation:

you multiply all numbers together to get 0.3

6 0
3 years ago
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