Help with math 360×610÷409= what help

Louann and Carla received equal scores on a test made up of multiple choice questions and an essay. Louann got 14 multiple choic

defon

Each multiple choice question was worth 5 points.

14x+24 = 16x +14
2x = 10
x = 5

4 0

3 years ago

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Can someone help please I need this asap

son4ous [18]

Answer:

PART:A

$10_P_4=5040$

PART:B

$6_C_2=15$

PART:C

$6_C_2=15$

Step-by-step explanation:

PART:A

When the four officers are chosen than the number of ways of doing this is:

$10_P_4$

since we have to choose 4 officers and also they need to be arranged according to their ranks.

Hence, the numbers of ways doing so is:

$10_P_4=\dfrac{10!}{(10-4)!}\\\\=\dfrac{10!}{6!}\\\\=10\times 9\times 8\times 7\\\\=5040$

PART:B

Now we have to choose 2 members out of the remaining 6 members so the we have to use combination since we have to just choose the members and do not have to rank them or in short we can say we do not have to arrange them.

Hence, the number of ways doing this is:

$6_C_2=\dfrac{6!}{2!\times (6-2)!}\\\\=\dfrac{6!}{2!\times 4!}\\\\=15$

Hence, the number of ways of doing this is: 15.

PART:C

Now this process of doing so is also same as the above.

Hence, the number of ways of doing so is: 15.

8 0

3 years ago

Determine the values of a for which the following system of linear equations has no solutions, a unique solution, or infinitely

navik [9.2K]

Answer:

Never

Step-by-step explanation:

The equations given are

2x1−6x2−4x3 = 6 ....... (1)

−x1+ax2+4x3 = −1 ........(2)

2x1−5x2−2x3 = 9 ..........(3)

the values of a for which the system of linear equations has no solutions

Let first add equation 1 and 2. Also equation 2 and 3. This will result to

X1 + (a X2 - 6X2) - 0 = 5

And

X1 + (aX2-5X2) + 2X3 = 8

Since X2 and X3 can't be cancelled out, we conclude that the value of a is never.

a unique solution,

Let first add equation 1 and 2. Also equation 2 and 3. This will result to

X1 + (a X2 - 6X2) - 0 = 5

And

X1 + (aX2-5X2) + 2X3 = 8

The value of a = never

infinitely many solutions.

Divide equation 1 by 2 we will get

X1 - 3X2 - 2X3 =3

Add the above equation with equation 3. This will result to

3X1 - 8X2 - 4X3 = 12

Everything ought to be the same. Since they're not.

Value of a = never.

4 0

4 years ago

Hey! i’ll give brainliest please help!

tigry1 [53]

Answer:

royal background is the answer

3 0

3 years ago

Using the figure of the bullseye above, what is the probability that a shooter will hit the 3rd ring? Express your answer as a p

melisa1 [442]

The probability of hitting the third ring is the same as finding what percentage is the area of the third ring out of the total area of the board.

The area of the third ring = The total area of the board - The area of the second circle.

Refer to the diagram below
The diameter for the whole circle = 32 in
The radius = 16 in
The area of the whole circle = π(16)² = 256π

The diameter for the second circle = 22 in
The radius = 11 in
The area of the second circle = π(11)² = 121π

The area of the third ring = 256π - 121π = 135π

Area of the third ring as a percentage of the total area = $\frac{135 \pi }{256 \pi } *100$ = 52.7%

7 0

3 years ago

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