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daser333 [38]
3 years ago
6

HELP ME NOWWWWWWWWWWWWW

Mathematics
1 answer:
Korolek [52]3 years ago
8 0

Answer:

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Step-by-step explanation:

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You might be interested in
If you roll a 6 sided die 4 times what is the probability of getting 3 2’s
sp2606 [1]

Answer:

1/6 x 1/6 x 1/6 = 1/36 x 1/6 = 1/216

You multiply the chances

Hope this helped

Step-by-step explanation:

5 0
3 years ago
Cw 11.1 backside v. V.
nika2105 [10]

Answers:

10.  28.3 cm²

11. 7.3 cm²

12. P: 32 yds, A: 76.8 sq yds

13. P: 64 units, A: 220.8 units

14.  50.3 cm²

15. 132.7 cm²

16. 9.7 in

17. 5.9 cm

18.  324.08 sq inches.

19. 39 cm²

20. 36.6 cm²

Step-by-step explanation:

10. Find the area of the shaded region.

It's a circle, let's first calculate its area, with the formula A = π * r²

A = π  * 6² = 36 π  = 113.1 cm²

The shaded area has a 90 degrees angle... so it's 1/4 of the whole circle.

The area of the shaded area of this circle is then: 113.1 * 1/4 = 28.275 cm²

Rounded to the tenths, that's of course 28.3 cm²

11. Find the area of the shaded region.

Again, let's first find the area of the complete circle, with A =  π * r²

A =  π * 4² = 16π  = 50.27 cm²

Now, let's find the angle for the shaded area.

A circle has 360 degrees, and we know the angles of 2 segments... so we can easily find the missing angle:

360 - 203 - 105 = 52

The shaded area has an arc of 52 degrees, so we multiply the area of the full circle by 52/360 to get the area of that shaded area:

(50.27 * 52) / 360 = 7.26 cm², rounded to the tenths: 7.3 cm²

12. Find perimeter AND area of this regular polygon.

The figure is a regular octagon (8 sides).

To calculate its perimeter, it's simply 8 times one side, so: 8 * 4 yd = 32 yds

For the area, you can view an octagon as 8 triangles joined together.  In this case, we have a base of 4 yds and a height of 4.8 yds, so the area of each triangle is: (4 * 4.8) /2 = 9.6, the total area of the octagon is then 8 * 9.6 = 76.8 yds

13. Find perimeter AND area of this regular polygon.

The figure is a regular octagon (8 sides).

To calculate its perimeter, it's simply 8 times one side, so: 8 * 8 = 64 units

For the area, you can view an octagon as 8 triangles joined together.  In this case, we have a base of 4 yds and a height of 4.8 yds, so the area of each triangle is: (8 * 6.9) /2 = 27.6, the total area of the octagon is then 8 * 27.6 = 220.8 units

14. Find the area of a circle of <u>radius</u> = 4 cm

We have a circle with a radius of 4 cm, we need to find its area.

The area of a circle is obtained by the formula: A = π * r²

We already have the value of r, so we will input it in the formula:

So, we'll have A = π * 4² = 16 * π = 50.27 cm²

Rounded to the tenths: 50.3 cm²

15. Find the area of a circle of <u>diameter</u> 13 cm

We have a circle with a diameter of 13 cm, we need to find its area.  To use the formula for the area, we need the radius, not the diameter.  Since the diameter is 13 cm, the radius is 6.5

The area of a circle is obtained by the formula: A = π * r²

So, we'll have A = π * 6.5² = 42.25 * π = 132.73 cm²

Rounded to the tenths: 132.7 cm²

16. Find the diameter of a circle with an area of 75 in².

We just used the area formula for a circle, based on the radius.  We'll process it in reverse from the area to get the radius... which will give us the diameter, so r² = A / π

We then have:  r² = 75 / π = 23.87

So, r = 4.88 (square root of 23.87), which we double to get the diameter: 9.76 in, rounded to 9.7 in.

17. Find the radius of a circle with an area of 108 cm².

We just used the area formula for a circle, based on the radius.  We'll process it in reverse from the area to get the radius, so r² = A / π

If we input the area given in the question into the formula, we have:  r² = 108 / π = 34.38 cm

So, r = 5.86 (square root of 34.38), rounded to 5.9 cm.

18. Find the area

We have here a half-circle with a triangle.

We just used the formula for the area of a circle, and we know the radius of that half-circle: 8 inches.

A = π * 8² = 64 * π = 201.06 sq inches, for the whole circle.

But we only have half of it, so 201.06 / 2 = 100.08 sq inches.

Now the triangle.  To calculate the area of a triangle, you multiply its base by its height, then you divide by 2, so:

A = 16 x 28 = 224 sq inches.

Which we add to the half-circle area (100.08 sq inches) to get 324.08 sq inches. So 324.1 sq inches once rounded to the tenths.

19. Find the area

We have a triangle on top of a rectangle.

Area of a triangle: (base * height) / 2.

Area of a rectangle: base * height

So, for the triangle: A = (6 * 3) / 2 = 9 cm²

And for the rectangle: A = 6 * 5 = 30 cm²

Total: 9 + 30 = 39 cm²

20. Find the area

We have a rectangle and a half circle.  The radius of the half-circle is: 2 cm (half of the height of the rectangle).

Area of the rectangle: base * height, so 6 * 4 = 24 cm²

Area of the circle:  π * r² = π * 2² = 4π = 12.56 cm²

Total for the figure: 24 + 12.56 = 36.56, or 36.6 cm² once rounded.

3 0
3 years ago
Find the measurement
xenn [34]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

6z + 7  = 8z - 9

8z - 9 = 6z + 7

Add sides 9

8z - 9 + 9 = 6z + 7 + 9

8z = 6z + 16

Subtract sides 6z

- 6z + 8z =  - 6z + 6z + 16

2z = 16

Divide sides by 2

\frac{2z}{2}  =  \frac{16}{2}  \\

z = 8

Thus ;

NP = 8z - 9

NP = 8(8) - 9

NP = 64 - 9

NP = 64 - 4 - 5

NP = 60 - 5

NP = 55

Done...

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

6 0
3 years ago
I need help please it’s due tomorrow.......
Sholpan [36]
Let
x-------> the width of the rectangular area
y------> the length of the rectangular area

we know that
y=x+15------> equation 1
perimeter of a rectangle=2*[x+y]
2x+2y <= 150-------> equation 2

substitute 1 in 2
2x+2*[x+15] <=150--------> 2x+2x+30 <=150----> 4x <=150-30
4x <= 120---------> x <= 30
the width of the rectangular area is at most 30 ft
y=x+15
for x=30
y=30+15------> y=45
 the length of the rectangular area is at most 45 ft

see the attached figure
the solution is<span> the shaded area</span>

4 0
3 years ago
Greatest common factor of 48,120
AlekseyPX
Hello. &#10;&#10;Let's figure this out.&#10;&#10;I'll list all the factors to help us answer your question. &#10;&#10;48: 1&#10;2&#10;3&#10;4&#10;6&#10;8&#10;12&#10;16&#10;24&#10;48&#10;&#10;120: 1&#10;2&#10;3&#10;4&#10;5&#10;6&#10;8&#10;10&#10;12&#10;15&#10;20&#10;24&#10;30&#10;40&#10;60&#10;120 &#10;&#10;We can see that the GREATEST common factor (GCF) between&#10;&#10;49 and 120 is: 24&#10;&#10;You're welcome.
5 0
3 years ago
Read 2 more answers
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