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What is the insurance premium for a 42-year old nonsmoking female ($6.75) who wants $125,000 in coverage?

Lera25 [3.4K]

Answer:

The question is missing the sample life insurance premium illustration as found in the attached.

The correct option based on the below calculation is A,$33.75

Step-by-step explanation:

A female non-smoker who wanted a coverage of $25,000 as found in attached the sample life insurance premium illustration would pay $6.75 in premium.

Based on the above, a female non-smoker who wanted a coverage of $125,000 has it premium computed thus:

premium=$125,000/$25,000*$6.75

premium=5*$6.75=$33.75

The correct option is A,$33.75

Download xlsx

8 0

3 years ago

Read 2 more answers

Use the given transformation to evaluate the integral. 9 x − 3y 2x − y dA, R where R is the parallelogram enclosed by the lines

hichkok12 [17]

$\displaystyle\iint_R(9x-3y)(2x-y)\,\mathrm dA$

$\begin{cases}u=x-3y\\v=2x-y\end{cases}\implies\begin{cases}x=\frac{3v-u}5\\y=\frac{v-2u}5\end{cases}\implies\mathrm dA=|\det J|\,\mathrm du\,\mathrm dv$

where $J$ is the Jacobian matrix for the transformation,

$J=\begin{bmatrix}u_x&u_y\\v_x&v_y\end{bmatrix}=\begin{bmatrix}-\dfrac15&\dfrac35\\\\-\dfrac25&\dfrac15\end{bmatrix}\implies|\det J|=\dfrac15$

We have

$9x-3y=8x+x-3y=\dfrac85(3v-u)+u=\dfrac{24v-3u}5$

so that the integral is

$\displaystyle\frac1{25}\int_9^{10}\int_0^{10}(24v-3u)v\,\mathrm du\,\mathrm dv=\boxed{\frac{4051}5}$

5 0

4 years ago

In the year 1985, a house was valued at $120,000. By the year 2005, the value had appreciated exponentially to $145,000. What wa

11Alexandr11 [23.1K]

Answer:

The annual growth rate between 1985 and 2005 is 0.95%

The value of the house in the year 2010 is $152,018

Step-by-step explanation:

Let the annual growth rate = r

Value of the house in year 1985 = $120,000

Value of the house in year 2005 = $145,000

Time (t) = 2005 - 1985

= 20 years

A = P (1 + r)^t

145000 = 120000 (1 + r) ^20

(1 +r)^20 = 145000 / 120000

(1 +r)^20= 1.2083

(1 +r)^20= (1.2083)^1/20

(1 +r)^20= 1.0095

r = 1.0095 - 1

r = 0.0095

r% = 0.0095 x 100

= 0.95%

Value of the house in year 2010

=145000(1 + r)^5

=145000 (1 + 0.0095)^5

= 145000 x 1.0484

=$152,018

3 0

3 years ago

HELP URGENT! WILL GIVE BRAINLIEST!!

marissa [1.9K]

Answer:

1) 8 2) 125 3) 1,680 4) 5,040 5) 3,024

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Here are the heights in inches of 10 professional basketball players: 66, 74, 76, 77, 78, 79, 80, 80, 82, 84. The mean of these

Dvinal [7]

Answer:

Question 4: The set has 66 as an outlier and removing it increases the mean by about 1.3 inches.

Question 5: The set has 50 as an outlier and removing it increases the mean by about 3.

Step-by-step explanation:

Question 4:

Given heights are:

66, 74, 76, 77, 78, 79, 80, 80, 82, 84

The mean is: 77.6 inches

Removing 66 will make the mean increase to 78.9

So,

The set has 66 as an outlier and removing it increases the mean by about 1.3 inches.

Question 5:

50, 74, 76, 77, 78, 79, 80, 80, 82, 84

The mean is 76.

We can clearly see that 50 is an outlier as it is quite less than the given data.

Calculating mean after removing 50 will give us mean equal to 78.9

So the correct answer is:

The set has 50 as an outlier and removing it increases the mean by about 3.

5 0

3 years ago