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kogti [31]
3 years ago
6

jalen jogged 10 miles due north, then turned due west and jogged 5 more miles. How msny miles is jalen from his starting point?

Mathematics
1 answer:
Juliette [100K]3 years ago
7 0

Answer:

Jalen is <u>11.18 miles</u> from his starting point.

Step-by-step explanation:

Given:

Jalen jogged 10 miles due north, then turned due west and jogged 5 more miles.

Now, to find miles Jalen jogged from his starting point.

So, below is the figure attached to describe the scene.

Now, to get the distance of Jalen jogged from his starting point we use pythagoras theorem:

AB^2+BC^2=AC^2\\\\10^2+5^2=AC^2\\\\100+25=AC^2\\\\125=AC^2

<em>Using square root on both sides we get:</em>

11.18=AC\\\\AC=11.18\ miles.

Therefore, Jalen is 11.18 miles from his starting point.

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At a raffle, 1500 tickets are sold at $2 each. There are four prizes given for $500, $250, $150, and $75. You buy one ticket. Us
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Answer:

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Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of tickets sold at the raffle = 1,500

Price of each ticket = $ 2

Total prizes = 1 * $ 500 + 1 * $ 250 + 1 * $ 150 + 1 * $ 75

2. Use a probability distribution table to calculate the expected value of your gain. Your expected value is_____ ?

Let's answer the question using a probability distribution for the gains, this way:

  • Probability of 1st prize of $ 498 (500 - ticket) = 1/1,500
  • Probability of 2nd prize of $ 248 (250 - ticket) = 1/1,500
  • Probability of 3rd prize of $ 148 (150 - ticket) = 1/1,500
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Now, we calculate the mean for all the tickets (winners and non-winners), this way:

Expected value = [(1,496 * -2) + (1 * 498) + (1 * 248) + ( 1 * 148) + ( 1 * 73)]/1,500

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Expected value = -2,025/1,500 = - 1,35

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Answer:

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Step-by-step explanation:

Let 2\cdot x_{1}+5\cdot x_{2} = -1\cdot h\cdot x_{1} + k\cdot x_{2} = 7, if this linear system has infinitely many solutions, then the following conditions must be met:

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The values of h and k for a linear system with infinitely many solutions are -2 and 5, respectively.

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