Answer:
thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)
Step-by-step explanation:
denoting A= a piece is defective , Bi = a piece is defective from the i-th supplier and Ci= choosing a piece from the the i-th supplier
then
P(A)= ∑ P(Bi)*P(C) with i from 1 to 3
P(A)= ∑ 5/100 * 24/100 + 10/100 * 36/100 + 6/100 * 40/100 = 9/125
from the theorem of Bayes
P(Cz/A)= P(Cz∩A)/P(A)
where
P(Cz/A) = probability of choosing a piece from Z , given that a defective part was obtained
P(Cz∩A)= probability of choosing a piece from Z that is defective = P(Bz) = 6/100
therefore
P(Cz/A)= P(Cz∩A)/P(A) = P(Bz)/P(A)= 6/100/(9/125) = 5/6 (83.33%)
thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)
Answer:
The last one, −2.1−(5.9+3.7)
Step-by-step explanation:
−2.1+(−5.9)+(−3.7) = -2.1-5.9-3.7 = -11.7
the only expression that will come out as -11.7 is the last one
Least to greatest 52, 63, 55, 56, 62, 54, 59, 60, 53, 61, 88
BartSMP [9]
Answer:
52, 53, 54, 55, 56, 59, 60, 61, 62, 88
Step-by-step explanation:
You need to start from 52 to 88 (least to greatest) and then you will get answer.
Answer:
68
Step-by-step explanation:
15% of 80 is 12 so you subtract 12 from 80 and thats 68.
Answer:
a. 15/23
b. 13/27
c. 400g
Step-by-step explanation:
a. When the denominators are the same, you can just sum the numerators.
Which becomes, 13+2=15--> 15/23
b. Same, when the denominator is the same, you can just minus the numerators. Which becomes, 25-12=13--> 13/27
c. 1kg=1000g. 1000/5=200✖️2=400
