Answer:
y=-5,x=2
Step-by-step explanation:
3x+3y=-9________________eqn 1
3x-3y=21________________eqn 2
using elimination method
3x+3y=-9
-
3x-3y=21
subtract equation 2 from equation 1
0+6y=-30
6y=-30
y=-30/6
y=-5
substitute the value of y in equation 1
3x+3y=-9
3x+3(-5)=-9
3x-15=-9
3x=-9+15
3x=6
x=6/3
x=2
X=cubic root 2/27
Glad to help
let
(hypotenuse ) c = 10 in
(perpendicular) a = 8 in
(base) b =?
By using Pythagoras theorem
c^2= a^2+b^2
(10)^2 = (8)^2 +(b)^2
100 = 64 +(b)^2
100- 64 = (b)^2
36 = (b)^2
√36 = b
6 = b
hence b= 6 in
1 unit to the left of -1 on the number line is -2.
Thus, 7 units to the left of -1 is -8.
The appropriate choice is ...
... c. -8
Answer:
Step-by-step explanation:
<u>Incenter is the intersection of angle bisectors.</u>
- ∠MJP = ∠OJP, ∠MKP = ∠NKP, ∠NLP = ∠OLP
<u>First find the value of x:</u>
- 7x - 6 = 5x + 4
- 7x - 5x = 4 + 6
- 2x = 10
- x = 5
<u>Find the angle MJP:</u>
<u>We know sum of interior angles of a triangle is 180°. Using this find the missing angle measure:</u>
- 2*m∠MJP + 2*m∠NJP + 2*m∠MKP = 180°
- m∠MJP + m∠NJP + m∠MKP = 90°
- 29° + 26° + m∠MKP = 90°
- m∠MKP = 90° - 55°
- m∠MKP = 35°
