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mash [69]
3 years ago
13

A quadrilateral has congruent diagonals. It is probably a( n) ______.

Mathematics
1 answer:
____ [38]3 years ago
7 0
<span>A quadrilateral has congruent diagonals. It is probably a <u>Square</u></span>
You might be interested in
Correct answers only please!
-Dominant- [34]

Answer:

63.4

Step-by-step explanation:

The triangle is right angled , so :

tan S = UT/ST

tan S = 2/1

tan S = 2

S = tan^{-1}2

S = 63.4

5 0
3 years ago
I need help with geometry plz
Softa [21]

Answer:

Point A is -2, 1

Point B is -4, -2

Point C is -4, -6

and D is -1, 3.

Step-by-step explanation:

Irdk if this is all right bcz its kinda hard to see the exact points. Hope it is tho, and hope it helps you out! Good luck :P

4 0
3 years ago
Y=(4x-5)(x-?) what does x equal
Whitepunk [10]
Set the factor '(4 + -1x)' equal to zero and attempt to solve: Simplifying 4 + -1x = 0 Solving 4 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1x = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1x = 0 + -4 -1x = 0 + -4 Combine like terms: 0 + -4 = -4 -1x = -4 Divide each side by '-1'. x = 4 Simplifying x = 4

Easy answer
Its 0

I hope it's correct Good luck...
8 0
3 years ago
11. Calvin walks 5 km south, then turns and walks 8 km east. Find his distance and displacement. Explain your answer.
Alecsey [184]

Answer:

Step-by-step explanation: the thing is that if kelvin walks 5km south and then 8 km east the displacement is that he won’t really make it to the east.

5 0
3 years ago
Consider the region bounded by
Montano1993 [528]
The equation is a circle centered at the origin with radius 8 (sqrt(64))
Therefore, the bounded region is just a quarter circle in the first quadrant.

Riemann Sum: ∑⁸ₓ₋₋₀(y²)Δx=∑⁸ₓ₋₋₀(64-x²)Δx

Definite Integral: ∫₀⁸(y²)dx=∫₀⁸(64-x²)dx
4 0
3 years ago
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