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Studentka2010 [4]
3 years ago
14

What is the approximate mass in kg of 151 L of water?

Mathematics
1 answer:
brilliants [131]3 years ago
6 0

Answer:

The answer will be 64.5

Step-by-step explanation:

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2 years ago
The monthly output P of a light bulb factory is given by the formula P = 450LK, where L is the amount invested in labor and K th
Tems11 [23]

Answer:

C(p)  = 4,96 (in thousands of dollars)

l = 2980 $  invest in labor

k = 2980 $ invest in equipment

Step-by-step explanation:

Information we have:

Monthly output   P = 450*l*k       ⇒  k = P/450*l

But the production need to be 4000

Then k = 4000/450*l

Cost of production = l * k     (in thousands of dollars)

C(l)  =  l  + 4000/450*l

Taking derivatives (both members of the equation)

C´(l) = 1 - 400 /45*l²          ⇒ C´(l) = 0          ⇒ 1 - 400/45l²  = 0

45*l² -  400  = 0              ⇒  l²  = 400/45

l = 2.98 (in thousands of dollars)

l = 2980 $ And

k = 400/45*l           ⇒  k 400/45*2.98

k = 2.98  (in thousands of dollars)

C(p) = l + k

C(p)  =  2980 + 2980  

C(p)  = 5960 $

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3 years ago
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Answer:

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