8/12 is equal to 2/3 because 2 x 4 and 3 x 4 equals 8/12
-4/9 is simplified of -12/27
Answer:
Equivalent to a), b), and d). It is NOT equivalent to c).
Step-by-step explanation:
6m + 12 is also equivalent to a) 3(2m+4) because when you distribute, it's 6m + 12. It is also equivalent to b) 3m + 8 + 4 + 3m because if you add them together, you get 6m + 12. It is not equivalent to c) but is do d) 4m + 2(m + 6) cause you use the distributive property then add. I hope this helped and please mark brainliest!
y = mx + b
y = 2x + 1
y - y₁ = m(x - x₁)
y - 4 = 2(x - 5)
y - 4 = 2(x) - 2(5)
y - 4 = 2x - 10
+ 4 + 4
y = 2x - 6
Answer:
C
Step-by-step explanation:
To make it easy let's start by organizing our information :
- AC=12 AND BD=8
- ABCD is a rhombus
- K and L are the midpoints of sides AD and CD
- we notice that the rhombus ABCD is divided into four right triangles
What do you think of when you hear a right triangle ?
- The pythagorian theorem !
AC and BD are khown so let's focus on them .
If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?
Simply because they are the diagonals of a rhombus .
ow let's apply the pythagorian theorem :
- (AC/2)² + (BD/2)² = BC²
- 6²+4²=52
- BC²= 52⇒
=BC
Now we khow that : AB=BC=CD=AD=
This isn't enough . Let's try to figure out a way to calculate the length of KL wich is the base of the triangle
- KL is parallel to AC
- k is the midpoint of AD and L of DC
I smell something . yes! Thales theorem
- KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
- KL/12=
/2*
- KL/12=1/2⇒ KL=6
Now we have the length of the base kl
Now the big boss the height :
- notice that you khow the length of KL
- BD crosses kl from its midpoint and DL =
/2
What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D
- DL²=(KL/2)²+D²
- 52/4= 9+ D²
- D² = 52/4-9 +4 SO D=2
now the height of the trigle is H= BD-D= 8-2=6
NOw the area of the triangle is :
- A=(KL*H)/2 ⇒ A= (6*6)/2=18
THE ANSWER IS 18 SQ.UN