Remember that a parallel line has the same slope...
So we already know the slope of the line containing point C is -4.
Using point slope equation, we can do...
y-y₁=m(x-x₁)
y-7= -4(x-4)
y-7- -4x+16
*Add seven to both sides...* y=-4x+23
There is you answer... hope this helps!
Answer:
Step-by-step explanation:
Given
Bisector: QS
Required
Determine PQR
Since PQR is bisected to PQS and RQS, we have that
Substitute expressions for PQS and RQS
Collect Like Terms
Divide both sides by 3
Solving for PQR;
Substitute 2 for x
About 11% - I first subtracted 250 from 282, to get 32. I then did 32/282 to get .11.... You round that out to about 11%
Log w (x^2-6)^4
Using log a b = log a + log b, with a=w and b=(x^-6)^4:
log w (x^2-6)^4 = log w + log (x^2-6)^4
Using in the second term log a^b = b log a, with a=x^2-6 and b=4
log w (x^2-6)^4 = log w + log (x^2-6)^4 = log w + 4 log (x^2-6)
Then, the answer is:
log w (x^2-6)^4 = log w + 4 log (x^2-6)
Given:
$90 good for 3 pax for 1 week.
a) $90 / 3 = $30 cost to feed each person in a week
b) $30 cost to feed each person * 5 persons = $150
c) $30 cost to feed each person * 6 persons in a family = $180
The formula derived from the above facts is:
Total cost = cost per person * no. of person * no. of weeks.
Assuming = 6 persons for 2 weeks
Total cost = 30 x 6 x 2
Total cost = 180 x 2
Total cost = 360 cost to feed a family of 6 in 2 weeks.
