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Alla [95]
2 years ago
7

Determine the approximate value of angle A​

Mathematics
1 answer:
kupik [55]2 years ago
6 0

answer

40°

step by step explanation

according to the figure the two angles are given

the sum of all angles of triangle is 180°

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2x-4=10 reverse order algebra
hjlf

Answer:

7

Step-by-step explanation:

2x-4=10

2x=10+4

2x=14

x=14/2

x=7

8 0
2 years ago
The side lengths of a right triangle are 18 cm, 24 cm, and 30 cm. You are asked to find the area of the triangle by using A = 1/
vekshin1

Answer:

1. Use the Adjacent and opposite side (Ignore the Hypotenuse)

Or use HERO'S FORMULA based on the information given

2. Area = 216cm^2

Step-by-step explanation:

There are three to four ways we can go about finding the area of a triangle. And a these would be dependent on the information given about the triangle.

From the question, you said the three side lengths are given. In such case, we employ the HERO FORMULA.

HERO FORMULA:

Area = √ s(s-a)(s-b)(s-c)

where s = 1/2(a + b + c)

a, b, c are the three sides

But since the question insisted that we use 1/2* base * height. Let's use our know of right angle to dissolve that.

A right angle triangle has three sides. The longest is always the Hypotenuse.

Let's take it this way.

Hypotenuse = 30cm

Opposite= 18cm

Adjacent = 24cm

Area = 1/2 * base * height

Area = 1/2 * 18 * 24

Area = 1/2 * 432

Area = 216cm^2

We ignored the longest side, (the Hypotenuse)

6 0
2 years ago
Ill give a brainliest <br> i need help its due today
aliya0001 [1]

Answer:

w=15

Step-by-step explanation:

-24=-3w+21

We move all terms to the left:

-24-(-3w+21)=0

We get rid of parentheses

3w-21-24=0

We add all the numbers together, and all the variables

3w-45=0

We move all terms containing w to the left, all other terms to the right

3w=45

w=45/3

w=15

8 0
3 years ago
Read 2 more answers
What is the value of y?
Schach [20]

The total angles of a triangle must add up to 180 degrees, so y = 64 degrees

6 0
3 years ago
2ᵃ = 5ᵇ = 10ⁿ.<br> Show that n = <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bab%7D%7Ba%20%2B%20b%7D%20" id="TexFormula1" titl
11Alexandr11 [23.1K]
There are two ways you can go about this: I'll explain both ways.
<span>
</span><span>Solution 1: Using logarithmic properties
</span>The first way is to use logarithmic properties.

We can take the natural logarithm to all three terms to utilise our exponents.

Hence, ln2ᵃ = ln5ᵇ = ln10ⁿ becomes:
aln2 = bln5 = nln10.

What's so neat about ln10 is that it's ln(5·2).
Using our logarithmic rule (log(ab) = log(a) + log(b),
we can rewrite it as aln2 = bln5 = n(ln2 + ln5)

Since it's equal (given to us), we can let it all equal to another variable "c".

So, c = aln2 = bln5 = n(ln2 + ln5) and the reason why we do this, is so that we may find ln2 and ln5 respectively.

c = aln2; ln2 = \frac{c}{a}
c = bln5; ln5 = \frac{c}{b}

Hence, c = n(ln2 + ln5) = n(\frac{c}{a} + \frac{c}{b})
Factorise c outside on the right hand side.

c = cn(\frac{1}{a} + \frac{1}{b})
1 = n(\frac{1}{a} + \frac{1}{b})
\frac{1}{n} = \frac{1}{a} + \frac{1}{b}

\frac{1}{n} = \frac{a + b}{ab}
and thus, n = \frac{ab}{a + b}

<span>Solution 2: Using exponent rules
</span>In this solution, we'll be taking advantage of exponents.

So, let c = 2ᵃ = 5ᵇ = 10ⁿ
Since c = 2ᵃ, 2 = \sqrt[a]{c} = c^{\frac{1}{a}}

Then, 5 = c^{\frac{1}{b}}
and 10 = c^{\frac{1}{n}}

But, 10 = 5·2, so 10 = c^{\frac{1}{b}}·c^{\frac{1}{a}}
∴ c^{\frac{1}{n}} = c^{\frac{1}{b}}·c^{\frac{1}{a}}

\frac{1}{n} = \frac{1}{a} + \frac{1}{b}
and n = \frac{ab}{a + b}
4 0
3 years ago
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