Answer:
The ball reaches a height of 29.25 ft after 1.125 seconds
Step-by-step explanation:
The maximum height of a parabola can always be found by looking for the vertex. You can find the x value (or in this case the t value) of a vertex by using -b/2a in which a is the coefficient of x^2 and b is the coefficient of x.
-b/2a
-(36)/2(-16)
-36/-32
1.125 seconds
Now to find the height, we input that value in for t
h = -16t^2 + 36t + 9
h = -16(1.125)^2 + 26(1.125) + 9
29.25 feet
Hmmm well may I ask what your doing with the shapes bc um well if you put them shapes in the circle/oval why is it hard? I don’t do this stuff I’m confused...
The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is
(x - x^2)^2 * sqrt(3)/4.
Integrating from x = 0 to x = 1, we have
[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4
= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144.
Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...
Wow...we have lots of numbers to go through. we know that a 6 sided figure is a hexagon and the interior angles add up to be 720°. so.....
∠A + ∠B + ∠ C + ∠D + ∠E + ∠F = 720°
(x - 60) + (x - 40) + 130 + 120 + 110 + (x - 20) = 720
3x + 240 = 720 (combined all like terms)
3x = 480 (subtracted 240 from both sides)
x = 160 (divided both sides by 3)
put the value of x into ∠A (x - 60) = 160 - 60 = 100
∠A = 100°
