Jenny is a 60% free-throw shooter. She gets to shoot a second free throw if and only if she makes her first shot. She can score
0 points (if she misses her first shot), 1 point (she makes her first but misses her second), or 2 points (she makes both shots). Suppose Jenny gains confidence after making her first free throw and the probability of her making the second free throw goes up to 70%. Now, what number of points is Jenny most likely to make when she shoots a one-and-one?
<span>Jenny is a 60% free-throw shooter. She gets to shoot a second free throw if and only if she makes her first shot. She can score 0 points (if she misses her first shot), 1 point (she makes her first but misses her second), or 2 points (she makes both shots). Suppose Jenny gains confidence after making her first free throw and the probability of her making the second free throw goes up to 70%. Now, what number of points is Jenny most likely to make when she shoots a one-and-one? A-"0"
Hoped This Helped, Chloezeen Your Welcome :)</span>
By inspection, you can see that adding either 3x or 4x to y yields the same result of 7, meaning that x must be 0. If x is 0, y must be 7, meaning that this equation has only one solution. Hope this helps!
