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2 years ago

Hey can u please help i will give brainliy if u get it right :)

Mathematics

1 answer:

KATRIN_1 [288]2 years ago

5 0

9514 1404 393

Answer:

400 minutes

Step-by-step explanation:

The cost of the first plan is ...

A = 14 + 0.15m . . . . . . . . where m is the number of minutes used

The cost of the second plan is ...

B = 30 + 0.11m

The costs will be equal when ...

14 +0.15m = 30 +0.11m

0.04m = 16 . . . . . . . . . . . . . subtract 14+0.11m from both sides

m = 400 . . . . . . . . . . . . . . . divide by 0.04

The plans will have the same cost for 400 minutes of calls.

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What is the midpoint between points (4,7) and (1,1)?

Maurinko [17]

Answer:

(2,4) is the answr

Step-by-step explanation:

4 0

3 years ago

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Marty is asked to draw triangles with side lengths of 4 units and 2 units, and a non-included angle of 30°. Select all the trian

777dan777 [17]

Answer:

The drawn in the attached figure

see the explanation

Step-by-step explanation:

First case

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\B=30^o$

Applying the law of sines

Find the measure of angle A

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(A)}=\frac{2}{sin(30^o)}$

$sin(A)=1$

$A=90^o$

Find the measure of angle C

In a right triangle

we know that

$B+C=90^o$ ----> by complementary angles

$B=30^o$

therefore

$C=60^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{c}{sin(60^o)}=\frac{2}{sin(30^o)}$

$c=2\sqrt{3}\ units$

therefore

The dimensions of the triangle are

$A=90^o$

$B=30^o$

$C=60^o$

$a=4\ units\\b=2\ units\\c=2\sqrt{3}=3.46\ units$

Second case

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\A=30^o$

Applying the law of sines

Find the measure of angle B

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(30^o)}=\frac{2}{sin(B)}$

$sin(B)=0.25$

using a calculator

$B=14.48^o$

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

$A+B+C=180^o$

$A=30^o\\B=14.48^o$

therefore

$30^o+14.48^o+C=180^o$

$C=135.52^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{a}{sin(A)}$

substitute the given values

$\frac{c}{sin(135.52^o)}=\frac{4}{sin(30^o)}$

$c=5.61\ units$

therefore

The dimensions of the triangle are

$A=30^o$

$B=14.48^o$

$C=135.52^o$

$a=4\ units\\b=2\ units\\c=5.61\ units$

see the attached figure to better understand the problem

4 0

3 years ago

HELP ASAP PLZ!!!!!!!!!!!!!! THANKS IN ADVANCED :)

taurus [48]

I think its the 30x + 20

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3 years ago

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-----------------------------\\\\
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set the derivative to 0, and check the critical points, there's only one anyway

and do a first-derivative test, to see if it's a maximum

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3 years ago

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