The distance from the center of dilation, P, to.the image vertice S' is; 6 units.
<h3>What is the distance from the center of dilation, P, to the image S'?</h3>
It follows from the task content that the center of dilation of the triangle QRS is point P and the length of segment PS in the pre-image is; 8 units.
Hence, since the dilation factor as given in the task content is; three-fourths, it therefore follows that the distance of point P to S' in the image is; (3/4) × 8 = 6units.
Read more on dilation;
brainly.com/question/10253650
#SPJ1
Answer:
74
Step-by-step explanation:
You just have to substitute r with 5.
Now, the equation looks like this:
Next, solve 
first according to PEMDAS
And equals 75
![\frac{\left[\begin{array}{ccc}1&5\\5\\\end{array}\right] }{75}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%265%5C%5C5%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%7D%7B75%7D)
Lastly, do 
which equals 74
![\frac{\left[\begin{array}{ccc}7&5\\-1\\\end{array}\right] }{74}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%265%5C%5C-1%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%7D%7B74%7D)
Therefore, 74 is your answer.
Answer:
6 more students
Step-by-step explanation:
hope this helps
Answer:
steps below
Step-by-step explanation:
x-a=0
x=a plug in xⁿ - aⁿ
xⁿ - aⁿ = aⁿ - aⁿ = 0
(x-a) must be a factor of xⁿ - aⁿ
