Which group has a slope of 4/5? HELPPPPPPP PLEASEEEE IM BEGGGINGGGGGG
2 answers:
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First, let's expand the right side. Now our equation is
Now, we gather all the terms with x in it on the left side, and the numbers without x on the right. We get:
And then we can make this
We divide both sides by 12 to get x on its own, so x = 13/12 or 1.08
Now, we gather all the terms with x in it on the left side, and the numbers without x on the right. We get:
And then we can make this
We divide both sides by 12 to get x on its own, so x = 13/12 or 1.08
Answer:
(x - 3)² - 16 = 0
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Subtract 7 from both sides
x² - 6x + 7 = 0 ← in standard form
with a = 1, b = - 6
Given a quadratic in standard form then the x- coordinate of the vertex is
= -
= -
= 3
Substitute x = 3 into the equation for y
y = 3² - 6(3) - 7 = 9 - 18 - 7 = - 16 ⇒ (h, k) = (3, - 16)
y = (x - 3)² - 16 = 0