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3 years ago

6

Find the next two terms in this sequence. 1/2, 3/4, 7/8, 15/16

2 answers:

Dominik [7]3 years ago

8 0

Answer 17/18 , 19,20

Step-by-step explanation:

Basile [38]3 years ago

8 0

Answer:

31/32

Step-by-step explanation:

Two is added to 1/2. The numbers added each time are doubled what they were.

2, 4, 8, 16

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30 POINTS! Monica paid sales tax of $1.50 when she bought a new bike helmet. if the sales tax rate was 5%, how much did the stor

avanturin [10]

Hmm... well, here ya go.

1.50 ÷ 0.05 = 30
So, the total is $30
As for the tax rate, including the total, it would be $31.50.

Hope I helped.

6 0

3 years ago

Read 2 more answers

A group of 2 adults and 4 children spent $38 on tickets to a museum. A group of 3 adults and 3 children spent $40.50 on tickets

Paraphin [41]

Answer:

Divide the 1st equation by 2

a + 2c = 19

Divide the 2nd equation by 3

a + c = 13.5

Subtract the 1st equation and the 2nd equation

c = 5.5

Substituting back into the 2nd equation will give:

a + 5.5 = 13.5

a = 8

Step-by-step explanation:

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4 years ago

1-8: TRUE OR FALSE Use trig to find the missing measure.

arsen [322]

I believe that its true hby?.

8 0

3 years ago

Drag the missing statements and reasons to the correct spot to complete the proof

morpeh [17]

Answer:

See attached

Step-by-step explanation:

Answer is attached

7 0

3 years ago

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago