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3 years ago

5s-(100+2s =4s-2(10+s) how much boxes would they need to sell to get a equal amount each group must sell to have equal profits.

Mathematics

1 answer:

antoniya [11.8K]3 years ago

6 0

5s-100-2s=4s-20-2s
3s-100. = 2s-20
+20. +20
3s-80. = 2s
-3s. -3s
-80. = -1s
-1 -1
80. = s

s=80

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Which of the following give an equation of a line that passes through the point (6/5,-19,5) and is parallel to the line that pas

Ilya [14]

Parallel lines, have the same slope, so the slope of the line through 0,0 and -2,-12, is the same as for the line running through (6/5,-19.5) as well, so what is it anyway?

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 0}}\quad ,&{{ 0}})\quad 
% (c,d)
&({{ -2}}\quad ,&{{ -12}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-12-0}{-2-0}\implies \cfrac{-12}{-2}\implies 6$

so, we're looking for the equation of a line whose slope is 6, and goes through (6/5,-19/5)

$\bf \begin{array}{lllll}
&x_1&y_1\\
% (a,b)
&({{ \frac{6}{5}}}\quad ,&{{ -\frac{19}{5}}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 6
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-\left( -\frac{19}{5} \right)=6\left(x-\frac{6}{5} \right)
\\\\\\
y+\cfrac{19}{5}=6x-\cfrac{36}{5}\implies y=6x-\cfrac{36}{5}-\cfrac{19}{5}\implies y=6x-\cfrac{55}{5}
\\\\\\
y=6x-11$

6 0

3 years ago

a committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer.

miss Akunina [59]

Answer:

$\frac{1}{990}$

Step-by-step explanation:

The full question:

"A committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman, ranking member, and treasurer. What is the probability of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current positions?"

The permutation of choosing 3 members from a group of 11 would be:

P(n,r) = $\frac{n!}{(n-r)!}$

Where n would be the total [in this case n is 11] & r would be 3

Which is:

P(11,3) = $\frac{11!}{(11-3)!}=\frac{11!}{8!}=11*10*9=990$

So there are total of 990 possible way and there is ONLY ONE WAY for them to be reassigned. Hence the probability would be:

1/990

8 0

3 years ago

Plzzzz help I’ll give u points or I will block you

ad-work [718]

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6 0

3 years ago

You have 5/6 cup of cocoa in your cupboard. A recipe for cookies calls for 2/5 cup of cocoa. How much cocoa would you have left

bixtya [17]

5/6-2/5= 13/30 .........

7 0

2 years ago

Isreal has $57 in the bank. He adds $32 to it each month. He wants to buy a bike that cost $435. Every month the bike's price is

wlad13 [49]

Answer:

Step-by-step explanation:

57 + 32x equals 435 - 10x

42 x equals 378

x equals 9

5 0

3 years ago