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2 years ago

HELP ME PLEASE, I'M GIVING YOU ALL MY POINTS ;-; (which is 25)

Mathematics

1 answer:

pishuonlain [190]2 years ago

5 0

The answer to 31,096 + 59,721 is 89,817 so B 89,800 is the best estimate

2nd- The answer to 69,896 - 42,901 is 26,995 so A 26,900 is the best answer

3rd- 630,429 - 27,811 is 602,618 so the best answer(s) would be A 630,400 and C 27,800

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Pleaseeeeeeeee please help me i can’t get anything wrong save me please

Olegator [25]

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2 years ago

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A stock trading company charges a commission of $10 per trade plus $0.025 per dollar value of stock traded. If your commission i

pickupchik [31]

Answer:

Value of the stock traded was $5200.

Step-by-step explanation:

In this question it is given that trading company charges commission of $10 per trade or transaction plus $.025 per dollar value of stock.We have to calculate the value of stock we traded if total commission (commission on trade value + commission on trade) is $140.

Let the value of stock traded was $x.

Then commission on value of the stock = x×.025

Commission on transaction = $10

Total commission = 140 = ( .025x + 10)

⇒.025x = 140-10 = 130

x = 130÷.025 = $5200

So the value of the stock = $5200

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2 years ago

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Find the value of 8!

lukranit [14]

Answer: B

Step-by-step explanation: 8! = (8*7*6*5*4*3*2*1) = 40,320

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2 years ago

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What is the line segment of DB

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48 units! This may be wrong but hoped it helped!

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2 years ago

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A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions

salantis [7]

Dimensions are length 20 meter and width 14 meter

Solution:

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

A rectangle has width that is 6 meters less than the length

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

The area of the rectangle is given by formula:

$Area = length \times width$

Substituting the values we get,

$Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0$

Solve the above equation by quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}$

$a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14$

Since, length cannot be negative, ignore a = -14

Thus solution of length is a = 20

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

6 0

3 years ago