Hello!
So you figure that 7/10-5/10=2/10 that leave you with 1/5 left over. So if you take that into effect, all you have to do it multiply those 3 gallons by 5. Which gives you 15. So, your answer would be 15 gallons.
I hope this helped!
I am, yours most sincerely
SuperHelperThingy
Answer:
(3,-5)
Step-by-step explanation:
Answer:
Solving the equation
using quadratic formula we get ![x=4+5i \ or \ x=4-5i](https://tex.z-dn.net/?f=x%3D4%2B5i%20%5C%20or%20%5C%20x%3D4-5i)
Step-by-step explanation:
We need to solve the equation
using quadratic formula.
The quadratic formula is:
![$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$](https://tex.z-dn.net/?f=%24x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D%24)
where a=1, b=-8 and c=41
Putting values in formula and finding x
![$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$\\$x=\frac{-(-8)\pm\sqrt{(-8)^2-4(1)(41)}}{2(1)}$\\$x=\frac{8\pm\sqrt{64-164}}{2}$\\$x=\frac{8\pm\sqrt{-100}}{2}$\\We \ know \ \sqrt{-1}=i\\x=\frac{8\pm10i}{2}\\x=\frac{8+10i}{2} \ or \ x=\frac{8-10i}{2}\\x=4+5i \ or \ x=4-5i](https://tex.z-dn.net/?f=%24x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D%24%5C%5C%24x%3D%5Cfrac%7B-%28-8%29%5Cpm%5Csqrt%7B%28-8%29%5E2-4%281%29%2841%29%7D%7D%7B2%281%29%7D%24%5C%5C%24x%3D%5Cfrac%7B8%5Cpm%5Csqrt%7B64-164%7D%7D%7B2%7D%24%5C%5C%24x%3D%5Cfrac%7B8%5Cpm%5Csqrt%7B-100%7D%7D%7B2%7D%24%5C%5CWe%20%5C%20know%20%5C%20%5Csqrt%7B-1%7D%3Di%5C%5Cx%3D%5Cfrac%7B8%5Cpm10i%7D%7B2%7D%5C%5Cx%3D%5Cfrac%7B8%2B10i%7D%7B2%7D%20%5C%20or%20%5C%20x%3D%5Cfrac%7B8-10i%7D%7B2%7D%5C%5Cx%3D4%2B5i%20%5C%20or%20%5C%20x%3D4-5i)
So, Solving the equation
using quadratic formula we get ![x=4+5i \ or \ x=4-5i](https://tex.z-dn.net/?f=x%3D4%2B5i%20%5C%20or%20%5C%20x%3D4-5i)
We have that
smaller figure
ha=8.7
ra=1.6
larger figure
hb=10.44
rb=1.92
ha/hb=8.7/10.44----> 0.83
ra/rb=1.6/1.92-------> 0.83
ratio smaller figure to the larger figure
1.6/1.92-------> divided by 1.6 both members[1.6/1.6]/[1.92/1.6]-------> 1/1.2
the ratio ha/hb is equal to the ratio ra/rb
so
the smaller figure and the larger figure are similar
and
the ratio smaller figure to the larger figure is equal to----> 1/1.2
the answer is
the option yes 1/1.2