Agents of erosion can be all of the following except

Biology

2 answers:

Ludmilka [50]3 years ago

7 0

D gravity :) is the correct answer

BARSIC [14]3 years ago

3 0

The answer is D. Gravity

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. For the following give the mRNA, tRNA and amino acid (a.a.) sequence that will be created:

alexdok [17]

<span>mRNA: UACAUGGCCUUACGCUAA tRNA: AUG UAC CGG AAU GCG AUU a.a: Tyrosine, Methionine, Alanine, Leucine, and Arginine DNA has 4 different bases, they are Adenine (A), cytosine (C), guanine (G), and Thymine (T). RNA also has 4 bases with three of them being identical to the DNA bases and Thymine being replaced with Uracil (U). These bases are generally represented by the 1st letter of their names. Each of the bases will join with a complementary base, so A always pairs with T or U, and C will pair with G. So to create the mRNA, simply replace every A with a U, every C with a G, every G with a C, and finally, every T with a A. So mRNA: UACAUGGCCUUACGCUAA Now for tRNA, there's a slight twist. It only comes in 3 base codons, You won't find a sequence of tRNA other than in 3 base codons. And each of those codons will be uniquely paired with an amino acid. In the ribosomes, the mRNA will be sequentially scanned 3 bases at a time allowing for a matching tRNA sequence to bind to the exposed 3 bases, this will cause the next amino acid to be bound into the protein being constructed. So split the mRNA into 3 base sequences and calculate the complement to get the tRNA. A simple shortcut is to look at the original DNA sequence and simply replace a T bases with U. So tRNA: AUG UAC CGG AAU GCG AUU Notice the spaces every 3rd base. THIS IS REQUIRED. These is no continuous length of tRNA. You'll only find it in 3 base lengths and each of them will be bound with an amino acid. For the amino acid that's coded to the RNA, you'll need to use a lookup table in your text book, or one you can find online. Then it's a simple matter of matching each 3 base sequence to the amino acid. For the sequence given we have: AUG - Tyrosine UAC - Methionine CGG - Alanine AAU - Leucine GCG - Arginine AUU - STOP Notice the AUU doesn't decode to a specific amino acid. It instead indicates to the ribosome to stop the production of the protein. So the amino acid sequence for the originally given DNA sequence is: Tyrosine, Methionine, Alanine, Leucine, and Arginine.</span>

8 0

3 years ago

In the female, the development of the "egg" halts during TWO stages, _________ and __________

earnstyle [38]

Answer: The blanks can be correctly filled up with prophase I and metaphase II.

Explanation:

In females, finite number of oocytes are present since birth. The process of oogenesis initiate in embryonic stage only. However, oogonia divide and mature to form primary oocytes. These primary oocytes start meiotic division but arrest in prophase I stage before birth.

After a girl attains puberty, one primary oocyte resumes its division each month during a menstrual cycle. The primary oocyte divides to form secondary oocyte and polar body.

Polar bodies degenerate after completing meiosis II. However, secondary oocyte halts its division again at metaphase II until fertilization takes place. Once fertilization takes place it completes its meiosis II and results into mature ovum and polar body.