Answer:
The correct answer will be option-neural tube, hindbrain, metencephalon,
Explanation:
The development of the brain during the embryogenesis takes place by the formation of a neural tube or the predecessor of the central nervous system.
The neural tube arises from the ectoderm layer of the gastrula where the anterior portion of the neural tube forms the brain.
The neural tube development results in the formation of three sacs filled vesicles in which the fist vesicle forms the forebrain, second forms the midbrain and the third vesicle forms the hindbrain.
Later development process divides the hindbrain into two new portions called metencephalon and myelencephalon where the metencephalon forms the cerebellum portion of the brain.
Thus, the selected order is the correct order.
When water from the oceans/seas evaporate up into the atmosphere.
Answer: <u>The spine</u>
Explanation:
In the study of animal anatomy,a landmark is a major point on the body that has biological significance. An anatomical landmark is a biologically-meaningful point in an organism.;these landmarks are used for the definition of corresponding anatomical points within species.
Posterior, describes a region that is at the back of the body.
Answer:
The correct answers are A. "crenation", B. "hemolysis", C. "hemolysis", D. "crenation" and E. "neither will occur".
Explanation:
0.9% (m/v) NaCl or 5.0% (m/v) glucose are isotonic solutions at which the cells will not suffer any harmful consequence. A solution with a higher concentration than the isotonic conditions would result in the cells crenation, while a solution with a lower concentration would result in the cells hemolysis. Therefore the consequences of putting the red cells to the solutions stated in the question are as following:
A: 3.21% (m/v) NaCl Solution = crenation (higher than 0.9% (m/v) NaCl)
B: 1.65% (m/v) glucose Solution = hemolysis (lower than 5.0% (m/v) glucose)
C: distilled H2O Solution = hemolysis (lower than 0.9% (m/v) NaCl or 5.0% (m/v) glucose)
D: 6.97% (m/v) glucose Solution = crenation (higher than 5.0% (m/v) glucose)
E: 5.0% (m/v) glucose and 0.9%(m/v) NaCl = neither will occur (equal to 5.0% (m/v) glucose and 0.9% (m/v) NaCl)
