Question

Please Please Please Please Help Me.... Show your work if you can. It'll be very helpful.

Answer 1

Answer:

The table can be filled as shown below.

Step-by-step explanation:

The first function is

$f(x)=4x+8$

Put different values of x and find values of f(x).

For x=-2

$f(-2)=4(-2)+8=0$

For x=-1

$f(-1)=4(-1)+8=4$

Similarly for x=0,1,2 the value of f(x) are 8,12,16 respectively.

The second function is

$f(x)=\frac{2}{3}x+8$

For x= -6

$f(-6)=\frac{2}{3}(-6)+8=4$

For x= -3

$f(-3)=\frac{2}{3}(-3)+8=6$

Similarly for x=0,3,6 the value of f(x) are 8,10,12 respectively.

The third function is

$f(x)=5^{x-2}+7$

For x= 2

$f(2)=5^{2-2}+7=8$

For x= 3

$f(3)=5^{3-2}+7=12$

Similarly for x=4,5,6 the value of f(x) are 32,132,632 respectively.

The fourth function is

$f(x)=(\frac{1}{4})^x-5$

For x=-4

$f(-4)=(\frac{1}{4})^{-4}-5=4^4-5=251$

For x=-3

$f(-3)=(\frac{1}{4})^{-3}-5=4^3-5=59$

Similarly for x=-2,-1,0 the value of f(x) are 11,-1,-4 respectively.