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sveticcg [70]
3 years ago
6

A particular airport has beacons on the ground 6 km out from the start of each runway. An airplane is directly over this beacon

and is at an angle of elevation from the runway of 8°. Calculate the direct line distance from the airplane to the start of the runway
Mathematics
1 answer:
hodyreva [135]3 years ago
8 0

Answer:

6.06 km

Step-by-step explanation:

The information given in the question can be represented by the three sides if a right angled triangle.

Let the direct line from the airplane to the start of the runway be represented by x. So that applying the appropriate trigonometric function, we have;

Cos θ = \frac{adjacent}{hypotenuse}

Cos 8^{o}  = \frac{6}{x}

0.9903 = \frac{6}{x}

⇒ x = \frac{6}{0.9903}

      = 6.0588

x = 6.06 km

The direct line from the airplane to the stat of the runway is 6.06 km.

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This is a really interesting question! One thing that we can notice right off the bat is that each of the circles has the same amount of area swept out of it - namely, the amount swept out by one of the interior angles of the hexagon. Let’s call that interior angle θ. We know that the amount of area swept out in the circle is proportional to the angle swept out - mathematically

θ/360 = a/A

Where “a” is the area swept out by θ, and A is the area of the whole circle, which, given a radius of r, is πr^2. Substituting this in, we have

θ/360 = a/(πr^2)

Solving for “a”:

a = π(r^2)θ/360

So, we have the formula for the area of one of those sectors; all we need to do now is find θ and multiply our result by 6, since we have 6 circles. We can preempt this but just multiplying both sides of the formula by 6:

6a = 6π(r^2)θ/360

Which simplifies to

6a = π(r^2)θ/60

Now, how do we find θ? Let’s look first at the exterior angles of a hexagon. Imagine if you were taking a walk around a hexagon. At each corner, you turn some angle and keep walking. You make 6 turns in all, and in the end, you find yourself right back at the same place you started; you turned 360 degrees in total. On a regular hexagon, you’d turn by the same angle at each corner, which means that each of the six turns is 360/6 = 60 degrees. Since each interior and exterior angle pair up to make 180 degrees (a straight line), we can simply subtract that exterior angle from 180 to find θ, obtaining an angle of 180 - 60 = 120 degrees.

Finally, we substitute θ into our earlier formula to find that

6a = π(r^2)120/60

Or

6a = 2πr^2

So, the area of all six sectors is 2πr^2, or the area of two circles with radii r.
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