y = 9ln(x)
<span>y' = 9x^-1 =9/x</span>
y'' = -9x^-2 =-9/x^2
curvature k = |y''| / (1 + (y')^2)^(3/2)
<span>= |-9/x^2| / (1 + (9/x)^2)^(3/2)
= (9/x^2) / (1 + 81/x^2)^(3/2)
= (9/x^2) / [(1/x^3) (x^2 + 81)^(3/2)]
= 9x(x^2 + 81)^(-3/2).
To maximize the curvature, </span>
we find where k' = 0. <span>
k' = 9 * (x^2 + 81)^(-3/2) + 9x * -3x(x^2 + 81)^(-5/2)
...= 9(x^2 + 81)^(-5/2) [(x^2 + 81) - 3x^2]
...= 9(81 - 2x^2)/(x^2 + 81)^(5/2)
Setting k' = 0 yields x = ±9/√2.
Since k' < 0 for x < -9/√2 and k' > 0 for x >
-9/√2 (and less than 9/√2),
we have a minimum at x = -9/√2.
Since k' > 0 for x < 9/√2 (and greater than 9/√2) and
k' < 0 for x > 9/√2,
we have a maximum at x = 9/√2. </span>
x=9/√2=6.36
<span>y=9 ln(x)=9ln(6.36)=16.66</span>
the
answer is
(x,y)=(6.36,16.66)
Point A' is at (-2,-2)
Point D' is at (-2,4)
Just multiply each coordinate by 2
We have to simplify and get the value of x from this inequality given:
Given inequality,
Now let's simplify by using distributive property,
We need to find x, so let's isolate x to the letter side of the inequality for calculation at ease.
Now, dividing -2 from both sides.
Note : As we are dividing a negative number from both sides, the sign of the inequality will be <u>reversed</u>.
Now subtracting -7 from both sides,
Or, Interval of the equal ![(- \infin, -7 ]](https://tex.z-dn.net/?f=%28-%20%5Cinfin%2C%20-7%20%5D)
#CarryOnLearning
<u>━━━━━━━━━━━━━━━━━━━━</u>
The answer would be B: F(x) = 6x - 12
This line passes through both given points.
Answer:
<em>12 scoops of dog food are needed for 6 dogs,</em>
Step-by-step explanation:
<u>Proportions</u>
The number of scoops of dog foods and the number of dogs are proportional variables.
We are given that 10 scoops of dog foods are used for 5 dogs. This gives a proportion of 10/5=2 scoops per dog.
We also know that 16 scoops are used for 8 dogs. The proportion is also 16/8=2 scoops per dog.
Thus, the constant of proportionality is 2.
For 6 dogs, you need to prepare 2*6 = 12 scoops of dog food.
12 scoops of dog food are needed for 6 dogs,
