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butalik [34]
2 years ago
9

I have one more question before im done so please help and have a good day.

Mathematics
1 answer:
3241004551 [841]2 years ago
6 0

Answer:

  • See below

Step-by-step explanation:

<h3>Part A</h3>

<u>Solve the equation:</u>

  • 6x² + 48x + 120 = 0
  • x² + 8x + 20 = 0
  • x² + 8x + 16 + 4 = 0
  • (x + 4)² + 4 = 0
  • (x + 4)² = - 4

The left side is positive and right side is negative so no solution

<h3>Part B</h3>

There is no intercession with the x-axis, the graph of the function is entirely above the x-axis.

It means the diver won't reach the bottom of the lake

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Answer: The Answer is 12

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3 years ago
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Note that WXYZ has vertices W(-1, 2), X(-5, 7), y(-1, -2), and Z (3, -7).
svp [43]

a. Slope of WZ = -2.25; Slope of WX = 5

b. WZ = √97; WX = √41

c. WXYZ is not a <em>rectangle, rhombus, nor a square</em>. We can conclude that: <em>D. WXYZ is none of these</em>.

<h3>Slope of a Segment</h3>

Slope = change in y/change in x

Given:

W(-1, 2), X(-5, 7), Y(-1, -2), and Z (3, -7)

a. Slope of WZ and slope of WX:

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Slope of WX = (7 - 2)/(-1 -(-1)) = 5

b. Use distance formula, d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}, to find WZ and WX:

WZ = \sqrt{(3 - (-1))^2 + (-7 - 2)^2}\\\\\mathbf{WZ = \sqrt{97} }

WX = \sqrt{(-5 -(-1))^2 + (7 - 2)^2}\\\\\mathbf{WX = \sqrt{41} }

c. The quadrilateral WXYZ have adjacent sides that are not perpendicular to each other and have different slopes and different lengths, so therefore, WXYZ is not a rectangle, rhombus, nor a square. We can conclude that: <em>D. WXYZ is none of these</em>.

Learn more about slopes on:

brainly.com/question/3493733

5 0
3 years ago
What is the answer to this along with steps to doing it?
pashok25 [27]
1/2*(2*8)=3*(-12)
1/2*16=3*(-12)
1/2*16= -36
8= -36
The equality is false because the left hand and right hand side are different
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4 years ago
Paula got $10.50 from her grandparents on her birthday. She earned $4.45 by babysitting. How much money is this in all? c HAPPY
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We have the following:

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