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3 years ago

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Solve 5c 4 = -26 a. 6 b. -6 c. -4.4 d. 3

1 answer:

lakkis [162]3 years ago

6 0

Simplifying 5C + -4 + -2C + 1 = 8C + 2 Reorder the terms: -4 + 1 + 5C + -2C = 8C + 2 Combine like terms: -4 + 1 = -3 -3 + 5C + -2C = 8C + 2 Combine like terms: 5C + -2C = 3C -3 + 3C = 8C + 2 Reorder the terms: -3 + 3C = 2 + 8C Solving -3 + 3C = 2 + 8C Solving for variable 'C'. Move all terms containing C to the left, all other terms to the right. Add '-8C' to each side of the equation. -3 + 3C + -8C = 2 + 8C + -8C Combine like terms: 3C + -8C = -5C<span>-3 + -5C = 2 + 8C + -8C Combine like terms: 8C + -8C = 0 -3 + -5C = 2 + 0 -3 + -5C = 2 Add '3' to each side of the equation. -3 + 3 + -5C = 2 + 3 Combine like terms: -3 + 3 = 0 0 + -5C = 2 + 3 -5C = 2 + 3 Combine like terms: 2 + 3 = 5 -5C = 5 Divide each side by '-5'. C = -1 Simplifying C = -1</span>

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3 years ago

A bank loaned out $21,500 , part of it at the rate of 11% annual interest, and the rest at 10% annual interest. The total intere

Luda [366]

Answer:

The loaned amount at 11 % is $ 19,000

The loaned amount at 10 % is $ 2,500

Step-by-step explanation:

Given as :

The total loan amount = $21,500

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The rate of interest are 11 % and 10 %

Let The loan amount at 11 % rate = $P

and The loan amount at 10 % rate = $21,500 - $P

Let The loan took for 1 year

Now,<u> From Simple Interest method </u>

Simple Interest = $\dfrac{\textrm Principal\times \textrm Rate\times \textrm Time}{100}$

$SI_1$ = $\dfrac{P_1\times R_1\times \textrm Time}{100}$

Or, $SI_1$ = $\dfrac{P\times 11\times \textrm 1}{100}$

Similarly

$SI_2$ = $\dfrac{21,500 - P\times 10\times \textrm 1}{100}$

∵ $SI_1$ + $SI_2$ = $2,340

Or, $\dfrac{P\times 11\times \textrm 1}{100}$ + $\dfrac{21,500 - P\times 10\times \textrm 1}{100}$ = $2,340

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Or, P = 234000 - 215000

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Hence The loaned amount at 11 % is $ 19,000

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3 years ago