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2 years ago

Solve 5c 4 = -26 a. 6 b. -6 c. -4.4 d. 3

1 answer:

6 0

Simplifying 5C + -4 + -2C + 1 = 8C + 2 Reorder the terms: -4 + 1 + 5C + -2C = 8C + 2 Combine like terms: -4 + 1 = -3 -3 + 5C + -2C = 8C + 2 Combine like terms: 5C + -2C = 3C -3 + 3C = 8C + 2 Reorder the terms: -3 + 3C = 2 + 8C Solving -3 + 3C = 2 + 8C Solving for variable 'C'. Move all terms containing C to the left, all other terms to the right. Add '-8C' to each side of the equation. -3 + 3C + -8C = 2 + 8C + -8C Combine like terms: 3C + -8C = -5C<span>-3 + -5C = 2 + 8C + -8C Combine like terms: 8C + -8C = 0 -3 + -5C = 2 + 0 -3 + -5C = 2 Add '3' to each side of the equation. -3 + 3 + -5C = 2 + 3 Combine like terms: -3 + 3 = 0 0 + -5C = 2 + 3 -5C = 2 + 3 Combine like terms: 2 + 3 = 5 -5C = 5 Divide each side by '-5'. C = -1 Simplifying C = -1</span>

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There are 28.35 g in an ounce and 2.21 lb in a kilogram. Juanita converts 3 kilograms to ounces. Is her conversion correct? Expl

GarryVolchara [31]

Answer:

3 kg = 105.82 ounces

Step-by-step explanation:

We have,

1 ounce = 28.35 g

and

1 kg = 2.21 lb

If we want to the value of 3 kg to ounces. The direct relation between kilogram to ounce is as follows :

1 kg = 35.274 ounces

It means,

3 kg = 105.82 ounces

So, the value of 3 kg is equal to 105.82 ounces.

4 0

2 years ago

Read 2 more answers

Write the number as hundredths in fraction form and decimal form. 9/10

Agata [3.3K]

0.09

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3 years ago

Which of the following values are solutions to the inequality 10+ x > 7?

Tanzania [10]

Answer:

Step-by-step explanation:

All the other options create a number that is smaller than 7, while the inequality suggests otherwise.

While, II create the number 9 - which is indeed bigger then 7

Glad to help ÷)

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3 years ago

PLease help if u can✊

Vaselesa [24]

Answer:

5 hours

Step-by-step explanation:

75 + 55x = 350

75 - 75 + 55x = 350 - 75

55x = 275

$\frac{55x}{55} = \frac{275}{55}$

x = 5

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3 years ago

For circle O, mCD=125° and m

Burka [1]

CA is a diameter of the circle, so $m\widehat{AC}=180^\circ$ , which means $m\angle AOB=m\angle AOD=m\widehat{AD}=180^\circ-m\widehat{CD}=55^\circ$ . Then $m\boxed{\angle ABO}=90^\circ-55^\circ=35^\circ$ .

This means $m\angle CBO=55^\circ-35^\circ=20^\circ$ . Also, if $m\angle AOB=55^\circ$ , then $m\angle BOC=180^\circ-55^\circ=125^\circ$ , which in turns tells us that $m\boxed{\angle BCO}=180^\circ-20^\circ-125^\circ=35^\circ$ .

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3 years ago