Solve 5c 4 = -26 a. 6 b. -6 c. -4.4 d. 3

1 answer:

6 0

Simplifying 5C + -4 + -2C + 1 = 8C + 2 Reorder the terms: -4 + 1 + 5C + -2C = 8C + 2 Combine like terms: -4 + 1 = -3 -3 + 5C + -2C = 8C + 2 Combine like terms: 5C + -2C = 3C -3 + 3C = 8C + 2 Reorder the terms: -3 + 3C = 2 + 8C Solving -3 + 3C = 2 + 8C Solving for variable 'C'. Move all terms containing C to the left, all other terms to the right. Add '-8C' to each side of the equation. -3 + 3C + -8C = 2 + 8C + -8C Combine like terms: 3C + -8C = -5C-3 + -5C = 2 + 8C + -8C Combine like terms: 8C + -8C = 0 -3 + -5C = 2 + 0 -3 + -5C = 2 Add '3' to each side of the equation. -3 + 3 + -5C = 2 + 3 Combine like terms: -3 + 3 = 0 0 + -5C = 2 + 3 -5C = 2 + 3 Combine like terms: 2 + 3 = 5 -5C = 5 Divide each side by '-5'. C = -1 Simplifying C = -1

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Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .