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trasher [3.6K]
2 years ago
15

Im not good at math at ALL i need help

Mathematics
2 answers:
zhuklara [117]2 years ago
8 0
Your answer is A. 31 and 14/29 is the simplest form.
kherson [118]2 years ago
6 0

Answer:

A

Step-by-step explanation:

So, what you do is 913 divided by 29 is 31.482 and so on, but when you round it and turn it into a mixed fraction, it's 31 in 14/29.

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(X^2+y^2)^2 polynomial identify. Simplify
Alexxx [7]

Answer:

(x^{2}+ y^{2})^{2} =x^{4}+2x^{2}y^{2}+y^{4}

Step-by-step explanation:

(X^2+y^2)^2 polynomial identify. Simplify

i.e

(x^{2}+ y^{2})^{2} = ?

Solution:

We have the identity,

(A+B)^{2}=A^{2}+2AB+B^{2}

In the Question

A=x^{2}

B=y^{2}

Substituting in the identity we get

(x^{2}+ y^{2})^{2} =(x^{2})^{2}+2(x^{2})(y^{2})+(y^{2})^{2}

Also we have

(x^{a})^{b} =x^{a\times b}

(x^{2}+ y^{2})^{2} =x^{4}+2x^{2}y^{2}+y^{4}  Which is the required

8 0
4 years ago
Find the side length of a cube with a volume of 422 yd ^3
Dmitry_Shevchenko [17]

Answer:

5.5 yd

Step-by-step explanation:

To find the side length of the cube, the volume is a clue. We know that all sides of a square are equal, and the volume of a cube is length×width×height. Since the length, width and height are all the same, we know it is V=x³. Since we know the volume, we can plug in and solve for x.

166=x³

In order to get x alone, we have to cube root both sides.

x≈5.5 yd

6 0
3 years ago
HELP ASAP PLEASE ❤️
RoseWind [281]

Answer:

sdd

Step-by-step explanation:

dgnzm.

3 0
3 years ago
100p for an answer please
jok3333 [9.3K]
It would be D I hope this helps
7 0
4 years ago
Read 2 more answers
What is the equation of the line that passes through 1,2 and is parallel to the line whose equation is 2x + y - 1 = 0
melamori03 [73]

Answer:

Step-by-step explanation:

Use the point-slope formula.

y - y_1 = m(x - x_1)    you have :  x_1 =1  and  y_1 =2

m the slope   m= -2 (same slope for the line : 2x+y-1=0 because this lines are parallel and you can write y=-2x-1

an equation for this line is : y-2 = -2(x-1)

7 0
4 years ago
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