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motikmotik
3 years ago
11

Jason is the captain of his basketball team the list below shows how many points Jason scored in each of the first 10 games 18,2

3,14,26,16,10,12,24,14,13 Part A: find the range, mean, median,and mode of Jason's scores. Part B: use your results from part a find the variance and standard deviation of Jason's scores. Part C: are your results from part b for sample or a population Part D: use your results from parts A - C to describe the shape of the distribution of Jason's scores
Please Help!!!
Mathematics
1 answer:
Anika [276]3 years ago
4 0
A. The scores in order are: 10, 12, 13, 14, 14, 16, 18, 23, 24, 26. The range is 26 - 10 = 16. The mean is the sum divided by 10, which is 17. The median is between 14 & 16, which is 15. The mode is 14, since it is repeated twice.
B. The variance is calculated by subtracting each score from the mean, squaring, and adding all such squares. Then divide by the number of terms (10) to get 27.6 Take the square root to get the standard deviation, which is 5.25.
C. This is for a population, since these are all 10 games that Jason played. (If it were a sample, we would divide by 9 only)

D. The mean of 17 is higher than the median of 15 and the mode of 14. This implies a left-skewed distribution. However, the SD of 5.25 is quite high relative to the mean of 17, so the distribution is not that clearly defined yet (more data points would make it clearer).
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The nth term of a sequence is given by 3n² + 11 Calculate the difference between the 6th term and the 9th term of the sequence.​
katovenus [111]

The difference between the 6th term and the 9th term of the sequence is 135

<h3>How to determine the difference</h3>

Given that the nth term is;

3n² + 11

For the 6th term, the value of n is 6

Let's solve for the 6th term

= 3( 6)^2 + 11

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For the 9th term, n = 9

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The difference between the 6th and 9th term

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Thus, the difference between the 6th term and the 9th term of the sequence is 135

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2 years ago
What minus 31 equals to 213
faltersainse [42]

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3 years ago
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nydimaria [60]
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3 years ago
If $1,000 is invested at 4% simple interest, how much will the investment be worth after 2 years? Please explain how compound an
Novay_Z [31]
<h3>Answer:</h3>
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  • compounded annually: $1081.60
<h3>Step-by-step explanation:</h3>

<em>Simple Interest</em>

Simple interest is computed on the principal amount only. Each year, 4% of the principal is added to the balance. So, at the end of 2 years, the balance is ...

... $1000 + 0.04×$1000 + 0.04×$1000

... = $1000×(1 + 0.04×2) = $1000×1.08

... = $1080.00

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<em>Comment on the computation</em>

The added interest is the rate (per year) multiplied by the number of years. Here, that is 0.04×2×(principal amount). The formula for the simple interest earned is often seen as ...

... I = Prt . . . . . where I is the amount of interest, P is the principal amount, r is the interest rate for the time period, t is the number of time periods.

The account balance (A) with interest added is ...

... A = P + I = P + Prt

... A = P(1 +rt)

Here, the time period is years, and the rate given is an annual rate.

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<em>Compound Interest</em>

Compound interest is computed on the <em>account balance</em> at the beginning of the period, not just the <em>principal</em> amount. After the first period, the account balance includes interest earned so far. So, the interest is earning interest. That is why it is called compounded interest.

Here, the balance at the end of the first year is the principal amount plus the interest that has earned:

... $1000 + 0.04×$1000 = $1000×1.04 = $1040.00

The balance at the end of the second year when the interest is compounded is this account balance plus the interest it earns:

... $1040 + 0.04×$1040 = $1040×1.04 = $1081.60

You may notice that the intial principal, $1000, has been multiplied by the factor 1.04 twice. Using exponents, the multiplier for a period of 2 years is 1.04×1.04 = 1.04².

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<em>Comment on the computation</em>

The multiplier of the account balance each year is raised to a power that is the number of years. Here, the account balance at the end of 2 years is (1+0.04)² times the principal amount. A formula that is seen for this is ...

... A = P(1 +r)^t . . . . . where A is the final account balance, P is the principal amount, r is the interest rate for the time period, and t is the number of time periods.

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3 years ago
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