Answer: Hence, the probability that he will get at least one lemon is 0.70.
Step-by-step explanation:
Since we have given that
Number of cars = 30
Number of lemon cars = 10
Number of other than lemon cars = 30-10 = 20
According to question, he bought 3 cars,
we need to find the probability that you will get at least one lemon.
So, P(X≤1)=1-P(X=0)=1-P(no lemon)
Here, P(no lemon ) is given by

so, it becomes,

Hence, the probability that he will get at least one lemon is 0.70.
PEMDAS
parenthesis, exponents, mult/division, add/subtract
parenthesis: 4+0.2= 4.2
exponents: 10^2= 10×10= 100
new equation: 10-5/100×0.4(4.2)
multiply/divide: 10-(1/20)×.4×4.2
10-(0.05)(0.4)(4.2)
10-0.002×4.2
add/subtract: 10-0.0084 = 9.9916
~this feels like a wrong answer~
Answer:
The expected number of admissions for the fall semester is approximately 1248 students.
Step-by-step explanation:
We are given the following information in the question:
Number of Students: 1,060 1,400 1,540
Probability: 0.61 0.11 0.3
Formula:

Expected number of admissions for the fall semester =

Hence, the expected number of admissions for the fall semester is approximately 1,248 students.
Answer:
3.16228
Step-by-step explanation:
There are several information's already given in the question. Based on those information's the answer can be easily deduced.
The equation given in the question is
T = 10x + 1000
When the ticket rate is increased to $15, the equation becaomes
T = 15x + 1000
4000 = 15x + 1000
15x = 3000
x = 200 tickets
From the above deduction, it can be concluded that the correct option among all the options that are given in the question is the third option or option "C".