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3 years ago

What are the steps on solving multi-step equations and inequalities

Mathematics

1 answer:

Aneli [31]3 years ago

7 0

Answer:

1)Clear parenthesis on both sides of the inequality and collect like terms.

2)Add or subtract terms so the variable is on one side and the constant is on the other side of the inequality sign.

3)Multiply and divide by whatever constants are attached to the variable.

Step-by-step explanation:

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If you have 13 oranges and u times it by 9 and than divide it by 3 add it to 65 take away 30 = ?????????? Wanna know

agasfer [191]

(13 x 9 / 3) + 65 - 30 = 74

7 0

3 years ago

Read 2 more answers

Jerry’s rhombus has a base of 15 inches and a height of 9 inches. Charlene’s rhombus has a base and a height that are 13 the bas

neonofarm [45]

Answer: The area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.

Step-by-step explanation:

I will assume that the exercise says " $\frac{1}{3}$ times the base and height of Jerry’s rhombus".

The area of a rhombus can be calculated with the following formula:

$A=b*a$

Where "b" is the length of the base and "a" is the altitude or the height.

Then, you can calculate the area using the formula shown above.

Therefore, you get:

1. Jerry's rhombus:

$A_1=(15\ in)(9\ in)\\\\A_1=135\ in^2$

2. Charlene's rhombus:

$A_2=(\frac{1}{3}*15\ in)(\frac{1}{3}*9\ in)\\\\A_2=(5\ in)(3\ in)\\\\A_2=15\ in^2$

Dividing the area calculated, you get:

$\frac{135\ in^2}{15\ in^2}=9$

Therefore, you can conclude that the area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.

7 0

3 years ago

Read 2 more answers

An amusement park offers ride tickets for $1.50 each to customers who buy the quantities of tickets indicated in the picture of

lara [203]

D. Customer who buy at least 25 tickets will pay $1.50 each

5 0

2 years ago

John, Jim and Joe each went for a medical examination. Their combined height was 5.25 m. If John was 12 cm shorter than Jim and

kolezko [41]

The 5.25 m combined height of John, Jim, and Joe, the 12 cm height difference between John and Jim and the 0.09 m difference in height between Jim and Joe, indicates that solution to the word problem is Joe was 1.73 meters tall

<h3>What is a word problem?</h3>

A word problem is a presentation of a math problem using verbal description rather than numbers, variables and operators.

The combined height of John, Jim and Joe = 5.25 m

John's height = Jim's height - 12 cm = Jim's height - 0.12

Jim's height = Joe's height + 0.09 m

Let <em>h </em>represent Joe's height, we get;

Jim's height = h + 0.09

John's height = h + 0.09 - 0.12 = h - 0.03

John's height = h - 0.03

The sum of the heights is therefore; h + h + 0.09 + h - 0.03 = 3·h + 0.06

The sum of their heights = Their combined height = 5.25 meters

Therefore; 3·h + 0.06 = 5.25

h = (5.25 - 0.06)/3 = 1.73

Joe's height, <em>h</em> = 1.73 meters

Jim's height = 1.73 + 0.09 = 1.82

Jim's height = 1.82 meters

John's height = 1.73 - 0.03 = 1.7

John's height is 1.7 meters

Joe was 1,73 meters tall

Learn more about mathematics word problems?

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4 0

1 year ago

Please help if u see this

jek_recluse [69]

<h3>Answer: Choice D</h3>

$(f \circ g)(x) = x+12$

Domain = [-3, infinity)

==================================================

Work Shown:

$f(x) = x^2 + 9\\\\f(g(x)) = (g(x))^2 + 9\\\\f(g(x)) = (\sqrt{x+3})^2 + 9\\\\f(g(x)) = x+3 + 9\\\\f(g(x)) = x+12\\\\(f \circ g)(x) = x+12\\\\$

In step 2, we replaced every x with g(x)

In step 3, we plugged in g(x) = sqrt(x+3)

The domain of g(x) is [-3, infinity), so this is the domain of $(f \circ g)(x)$ as well since the composite function depends entirely on g(x). Put another way: the input of f(x) depends on the output of g(x), so that's why the domains match up.

7 0

2 years ago