The domain in this equation is -7<x<infinty and the range is negative infinty<y<1.5
Answer:
B
Step-by-step explanation:
Recall that functions are defined only if for each value in the domain produces one and only one value in the range.
If we view the relations in the questions as x-y coordinates, this means that for every x-value, you can only have one y-value
Lets evaluate the options:
A) we can see that for x = -3, this gives 2 possible values for y i.e (-3,4) and (-3,8) (hence this is not a function)
C) we can see that for x = 3, this gives 2 possible values for y i.e (3,-8) and (3,8) (hence this is not a function)
D) we can see that for x = -3, this gives 2 possible values for y i.e (-3,4) and (-3,8) (hence this is not a function)
the only choice where this doesn't occur is choice B
Answer:
Step-by-step explanation:
I'm thinking cu
Please, write "x^3" for "the cube of x," not "x3." "^" denotes exponentiation.
Then you have g(x) = x^3 - 5 and (I assume) h(x) = 2x - 2.
1) evaluate g(x) at x = -2: g(-2) = (-2)^3 - 5 = -8 - 5 = -13
2) let the input to h(x) be -13: h(-13) = 2(-13) - 2 = -28 (answer)
